Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
Answer: Option
Explanation:
Total time taken = | ![]() |
160 | + | 160 | ![]() |
= | 9 | hrs. |
64 | 80 | 2 |
![]() |
![]() |
320 x | 2 | ![]() |
= 71.11 km/hr. |
9 |
Discussion:
63 comments Page 4 of 7.
Akshay Patel said:
6 years ago
Avg speed of x and y be x+y/2.
Then given that 64+80/2=72.
Then given that 64+80/2=72.
Nishit said:
6 years ago
@All.
Average speed means time is constant. So time would be same. Right?
Average speed means time is constant. So time would be same. Right?
Rahul said:
4 years ago
Thanks @Sundar.
Samy said:
1 decade ago
Thank you suguraman.
S.DineshKumar said:
2 decades ago
Can you explain how 9/2 hrs came ...
Can you explain the question ones again?
Can you explain the question ones again?
Ranjith said:
2 decades ago
while using the formula for avg speed, as nisha said it gives a different answer..
KOMAL said:
2 decades ago
THANKS TO SUNDER WHO GIVES A GOOD SOLUTION
Renuka said:
1 decade ago
Hi Sundar, very nice explaination, thank you so much.
Priya said:
1 decade ago
@sunder Thanks.
Prveen Bilimoga said:
1 decade ago
I have a doubt, can we do like this, the first 160 hrs is 64 km speed, and the second hr is 80, total 144. so 144/2 = to 72
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