Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 9)
9.
A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is:
35.55 km/hr
36 km/hr
71.11 km/hr
71 km/hr
Answer: Option
Explanation:

Total time taken = 160 + 160 hrs. = 9 hrs.
64 80 2

Average speed = 320 x 2 km/hr = 71.11 km/hr.
9

Discussion:
63 comments Page 4 of 7.

Ajay said:   8 years ago
Total speed 320km/hr.

64km/h + 80km/hr= 144km/hr.
So the average speed is 144/2= 72 km/hr.

Shivani said:   8 years ago
Sir, it is asking for 320 km so how can we apply this formula 2xy/ (x+y)?

Jitender Yaggik said:   8 years ago
@ALL.

Some of my friends are confused in Speed formulas some are using a+b/2 and some are using 2ab/a+b. Now I am going to clear that point, first of all when the distance is same In both then we will use the second formula which is Harmonic mean (2ab/a+b) and when the time is same in both cases then we will use Arithmetic mean a+b/2.

Thank you.

Swapnil said:   9 years ago
(64+80)/2 = 72.

This answer aprox to 71.11
Therefore the answer is 71.11.

Gayathri said:   9 years ago
@Sundar. Your explanations always make me clear, Thanks.

Rahul said:   9 years ago
Why can't we use 64 + 80/2 = 72?
(1)

Roksana1 said:   9 years ago
I'm using solution in this way. Whether it is correct way let me know.

Distance 1 = 160km.
Speed 1 = 64km/hr.

Distance 2 = 160km.
Speed 2 = 80km/hr.

If average distance is 320km.

Then let assume Avg speed = x.

So,

160/64 + 160/80 = 320/x.

20/8 + 16/8 = 320/x (to make the calculation easy let shortleft handed => 20 + 16/8= 320/x numbers).

=> 36/8 = 320/x.

x = 2560/36.
x = 71.11km/hr.

Vengatesh said:   9 years ago
Super, Thank you all.

Laxmi said:   9 years ago
Excellent way of clarifying the doubts.

Damodhar said:   1 decade ago
Average speed = (2*80*64)/(64+80) = 71.11.


Post your comments here:

Your comments will be displayed after verification.