Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 7)
7.
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
220 km
224 km
230 km
234 km
Answer: Option
Explanation:

(1/2)x + (1/2)x = 10
21 24

x + x = 20
21 24

15x = 168 x 20

x = 168 x 20 = 224 km.
15

Discussion:
141 comments Page 11 of 15.

Ketaki said:   1 decade ago
If any object does journey in 'T' hours the 1st half at a km/hr and 2nd half at b km/hr the total distance is :(2*T*a*b)/(a+b).

GHUHI said:   1 decade ago
5*21 = 105 KM.
5*24(KM/HR) = 120 KM.

SO TOTAL DISTANCE TRAVEL.
105+120 = 225.

Sri said:   1 decade ago
USE FORMULA :

Suppose a man covers a certain distance at x km/hr and an equal distance at y km/hr. Then,

The average speed during the whole journey is,

= 2(X)(Y)/(X)+(Y).
= 2(21)(24)/21+24.
= 1008/45.
= 22.4KM (AVERAGE SPEED).

NOW WE KNOW THE SPEED, SO SPEED = DISTANCE/TIME.
22.4 = DISTANCE/10 (MULTIPLYING 22.4 * 10 WE GET 224)
224 KMS.

Mohit said:   1 decade ago
Can't we solve like this:

21*5=105 and 24*5=5 which equal to 225 instead of 224 why?

Pavan V D said:   1 decade ago
(1/2)x/21+(1/2)x/24 = 10.
x/21+x/24 = 20.

Take LCM,
45x/504 = 20.

x/11.2 = 20.
x = 224.0km.

Chandan pal said:   1 decade ago
Avg speed: 2xy/x+y.

Avg speed: 2*21*24/21+24 = 112/5.

Distance = (112/5)*10 = 224.

Leelakrishna said:   1 decade ago
2/v = (1/v1)+(1/v2) find v then d = v*t.

Vissu said:   1 decade ago
Its simple. Average of two speeds 21 kmphr and 24 kmphr is 1008/45.

Now dist = speed x time = (1008/45) x 10 = 224.

Manhar said:   1 decade ago
Hi @Vikash.

Let the total distance = X (becoz we don't know the total distance or journey).

So, 1st half means X/2, 2nd half means also X/2.

That's why we can multiplied with(1/2) in first step.

S.vikash said:   1 decade ago
How you multiplied with (1/2) in first step?


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