Aptitude - Time and Distance - Discussion

Discussion Forum : Time and Distance - General Questions (Q.No. 7)
7.
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.
220 km
224 km
230 km
234 km
Answer: Option
Explanation:

(1/2)x + (1/2)x = 10
21 24

x + x = 20
21 24

15x = 168 x 20

x = 168 x 20 = 224 km.
15

Discussion:
141 comments Page 10 of 15.

Damodhar said:   1 decade ago
Average speed = (2*21*24)/(21+24) = 102/5.

Distance = (102*10)/5 = 224.

MALLIKARJUN said:   1 decade ago
Simple trick.

Find average speed because they are given half and half journey.

2xy/x+y......> 2(21)(24)/(21+24).

So average speed = 2(21)(24)/45.

Therefore D = S*T.

= [2(21)(24)/45]*10 = 224.

Velu said:   1 decade ago
There said half the journey. So why didn't we get half the time for calculation.

Like (5*24)+(5*21) = 225.

Gayu said:   1 decade ago
I can't understand this problem. Please explain.

Ab rahuman said:   1 decade ago
Use average speed formula 2xy/x+y and multiply with time.

Since Distance = Time*Speed.

Sajan said:   1 decade ago
Simple formula is 2t(s1*s2)/s1+s2.

So, 2*10(21*24)/21+24.

= 20*504/45.

= 20*11.2.

= 224.

Ranjitha said:   1 decade ago
How you get 20?

Kavitha said:   1 decade ago
How you got LCM as 45x/105?

Suresh Mahiya said:   1 decade ago
Average speed = 2*21*24/21+24.
= 22.4km/hr.

So Total Journey will be = speed * time.
= 22.4*10.
224 km.

Sakpal poonam said:   1 decade ago
Total average speed = (2*24*21)/(21+24).

Speed = 1008/45.
Distance = speed/time.

= (1008/45)/10.
= 224 km.


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