Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1
hours, it must travel at a speed of:
hours, it must travel at a speed of:Answer: Option
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
 Required speed = |
 |
1200 x | 3 |  km/hr |
= 720 km/hr. |
| 5 |
Discussion:
160 comments Page 2 of 16.
Prabakaran said:
7 years ago
On the first, the trail the aeroplane cross the distance in 5 hours at the speed of 240 km/hr.
For the same distance in 1(2/3) hours to resolve this cross multiplication (3*1*2-3= 3 hr).
So we have to multiply 240*3 to get the value of second trail speed is 720 km/hr.
For the same distance in 1(2/3) hours to resolve this cross multiplication (3*1*2-3= 3 hr).
So we have to multiply 240*3 to get the value of second trail speed is 720 km/hr.
Deepak said:
10 years ago
Distance = 240, 5 hour.
To cover same distance = x, 5/3 hour.
1 hour = 60 minutes, 5 hour = 300 minutes, 5/3 hour = 100 minutes.
= (5/3*60 minutes = 100 minutes).
= 240*300 = x*100.
72000 = x*100.
x = 72000/100.
x = 720.
So speed is 720 kmph.
To cover same distance = x, 5/3 hour.
1 hour = 60 minutes, 5 hour = 300 minutes, 5/3 hour = 100 minutes.
= (5/3*60 minutes = 100 minutes).
= 240*300 = x*100.
72000 = x*100.
x = 72000/100.
x = 720.
So speed is 720 kmph.
Penumaka abhi said:
7 months ago
Given distance = 240.
Time = 5hours,
Dis = speed * time.
D = 240 * 5 = 1200.
Another dis=1 2 ÷ 3(mixed fraction is given)is converted into 5/3.
Dist= 1200÷5/3(divided by 5/3 is inverse isconverted 3/5).
D = 1200 ÷ 3/5 = 720.
1200 * 3/5 = 720.
Time = 5hours,
Dis = speed * time.
D = 240 * 5 = 1200.
Another dis=1 2 ÷ 3(mixed fraction is given)is converted into 5/3.
Dist= 1200÷5/3(divided by 5/3 is inverse isconverted 3/5).
D = 1200 ÷ 3/5 = 720.
1200 * 3/5 = 720.
(6)
Majji deepika said:
1 month ago
Given data:
Speed = 240km/hr.
t = 5hr.
By the way, to cover the same distance in another time t1 = 5/3.
Speed = distance/time.
dis = speed * time
dis = 240 * 5
dis = 1200km.
Speed = dis/time.
Speed = 1200/(5/3).
Speed = 3600/5 = 720km/hr.
Speed = 240km/hr.
t = 5hr.
By the way, to cover the same distance in another time t1 = 5/3.
Speed = distance/time.
dis = speed * time
dis = 240 * 5
dis = 1200km.
Speed = dis/time.
Speed = 1200/(5/3).
Speed = 3600/5 = 720km/hr.
(6)
Govindraj said:
1 decade ago
Shortcut:
Because Distance traveled by Aeroplane is Same with different speed.
If speed ratio is "a:b" then time ratio will be "b:a" for same distance. So,
240:x = (5/3) :5 here 1 to the 2/3 = 5/3.
240:x = 1/3.
x = 240*3 = 720.
Because Distance traveled by Aeroplane is Same with different speed.
If speed ratio is "a:b" then time ratio will be "b:a" for same distance. So,
240:x = (5/3) :5 here 1 to the 2/3 = 5/3.
240:x = 1/3.
x = 240*3 = 720.
Abhishek sunny said:
1 decade ago
Those who says the answer is 720kmph please concentrate on my statement----.
If the answer is 720kmph then it means if we multi 720kmph with the given time of 1hr then we get the this which is 1200km isn't.
But did we get it?!
If the answer is 720kmph then it means if we multi 720kmph with the given time of 1hr then we get the this which is 1200km isn't.
But did we get it?!
Jolsana said:
1 year ago
Given,
Speed = 240kmph.
T1 = 5 hours.
According to the formula,
Distance = speed * time.
= 240 * 5 = 1200km.
T2 = 5/3 hours.
Speed = distance/time.
= 1200*3/5.
= 720kmph.
Speed = 240kmph.
T1 = 5 hours.
According to the formula,
Distance = speed * time.
= 240 * 5 = 1200km.
T2 = 5/3 hours.
Speed = distance/time.
= 1200*3/5.
= 720kmph.
(31)
Namrata Bajpai said:
9 years ago
A/Q as the distance is same.
So, d1 = d2.
We know that D = S/T.
So, S1 * T1 = S2 * T2 ----> (1).
Already, we have the value of s1= 240, t1 = 5, s2 = ?, t2 = 5/3.
So, according to the equation 1, we get S2 = 720.
So, d1 = d2.
We know that D = S/T.
So, S1 * T1 = S2 * T2 ----> (1).
Already, we have the value of s1= 240, t1 = 5, s2 = ?, t2 = 5/3.
So, according to the equation 1, we get S2 = 720.
Chandra Bhushan said:
1 decade ago
An aeroplane leaves late by 30 minutes. It has to cover a distance of 1200Km. The pilot has to increase its speed by 200Km/Hr to reach its destination on time. Find out the original speed of the aeroplane.
Rajesh said:
1 decade ago
Total distance covered in 5 hrs = (240*5) = 1200 kms.
We have to cover 1200 kms in 1(2/3)hrs, which is 100 min.
Therefore for 1 min we should cover (1200/100) = 12 kms.
For 60 min(1hr) = (12*60) = 720.
We have to cover 1200 kms in 1(2/3)hrs, which is 100 min.
Therefore for 1 min we should cover (1200/100) = 12 kms.
For 60 min(1hr) = (12*60) = 720.
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