Aptitude - Time and Distance - Discussion
Discussion Forum : Time and Distance - General Questions (Q.No. 2)
2.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1
hours, it must travel at a speed of:
hours, it must travel at a speed of:Answer: Option
Explanation:
Distance = (240 x 5) = 1200 km.
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]
 Required speed = |
 |
1200 x | 3 |  km/hr |
= 720 km/hr. |
| 5 |
Discussion:
162 comments Page 16 of 17.
Darshan said:
2 decades ago
Aeroplane travels total of 1200km to cover same distance in 1 hour it should travel wit 1200 kmph right but how come 720 kmph ?
Neelam said:
2 decades ago
Actually this is not speed, it must be the distance. As it is derived from the formula s*t=d. Hope it clears the confusion.
V P Samy said:
2 decades ago
I have doubt in 5/3.
5*240=1200km
1*(sp)=1200km
.'.Speed=1200km/hr this is correct or not ?
5*240=1200km
1*(sp)=1200km
.'.Speed=1200km/hr this is correct or not ?
M.Balaji said:
2 decades ago
d1=d2
240*5=x*(5/3)
3600=x*5
x=720(km/hr) If both are available in kmphr other we convert them as same.
It is very useful to students. I like this site.
240*5=x*(5/3)
3600=x*5
x=720(km/hr) If both are available in kmphr other we convert them as same.
It is very useful to students. I like this site.
Ramya said:
2 decades ago
Distance=240*5=1200
1+2/3=5/3
REQUIRED SPEED=(1200/5/3)
=(1200*3/5)
=720KM/HR
1+2/3=5/3
REQUIRED SPEED=(1200/5/3)
=(1200*3/5)
=720KM/HR
Ankit said:
2 decades ago
Correct mohit. !
Pandu said:
2 decades ago
How to give 3/5?
Sree said:
2 decades ago
Hello! Shwetha, You want to take it as comparison of two plan.
First Plan : 240km * 5hr = 1200km/hr
Second Plan: ? *1+(2/3)= 1200km/hr
First Plan : 240km * 5hr = 1200km/hr
Second Plan: ? *1+(2/3)= 1200km/hr
Shwetha shree said:
2 decades ago
D= S*T that's why 240 * 5.
Srinivasan.S said:
2 decades ago
The distance wants cover with 1+(2/3)hour is 1200km.
1 + (2/3) = (3+2)/3 = 5/3.
speed=Distance/time
speed=1200km/(5/3)
speed=1200km*(3/5)
speed=720km/hr
1 + (2/3) = (3+2)/3 = 5/3.
speed=Distance/time
speed=1200km/(5/3)
speed=1200km*(3/5)
speed=720km/hr
(1)
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