Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 14)

Surds and Indices

14.

x^b

(b + c - a)

x^c

(c + a - b)

x^a

^{(a + b - c)}

= ?

x^c

x^a

x^b

x^abc

x^{ab + bc + ca}

x^{a + b + c}

Answer: Option

Explanation:

Given Exp.

= x^{(b - c)(b + c - a)} . x^{(c - a)(c + a - b)} . x^{(a - b)(a + b - c)}

= x^{(b - c)(b + c) - a(b - c)} . x^{(c - a)(c + a) - b(c - a)}
. x^{(a - b)(a + b) - c(a - b)}

= x^{(b² - c² + c² - a² + a² - b²)} . x^{-a(b - c) - b(c - a) - c(a - b)}

= (x⁰ x x⁰)

= (1 x 1) = 1.

Discussion:

22 comments Page 3 of 3.

Dhanashree said: 1 decade ago

Little complicated sum please explain from 2nd step.

Mayuran said: 1 decade ago

2nd step is confused. Please explain.

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