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Aptitude - Surds and Indices - Discussion

Discussion Forum : Surds and Indices - General Questions (Q.No. 14)
Surds and Indices
14.
xb (b + c - a) . xc (c + a - b) . xa (a + b - c) = ?
xc xa xb
xabc
1
xab + bc + ca
xa + b + c
Answer: Option
Explanation:
Given Exp.
= x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c)
= x(b - c)(b + c) - a(b - c)  .  x(c - a)(c + a) - b(c - a)
   .  x(a - b)(a + b) - c(a - b)
= x(b2 - c2 + c2 - a2 + a2 - b2)  .   x-a(b - c) - b(c - a) - c(a - b)
= (x0 x x0)
= (1 x 1) = 1.
Discussion:
22 comments Page 2 of 3.
Ajay said:   1 year ago
Very useful question and thanks for all the given explanation.
Rita said:   7 years ago
I can't understand 2nd step, Please, someone explain to me.
Sachin said:   7 years ago
I can't understand the 2nd step. Please, anyone explain it.
Raj said:   4 years ago
I can't get 3rd step, can anyone, explain to me? please.
(1)
Karan said:   9 years ago
Dot (.) is multiplication sigh you can use x or (.).
Dhanashree said:   1 decade ago
Little complicated sum please explain from 2nd step.
Shivam Raj said:   8 years ago
Can anyone explain the 2nd step in easy solution?
Ankit singhai said:   9 years ago
x^(b - c)(b + c - a) How it is possible?
Mayuran said:   1 decade ago
2nd step is confused. Please explain.
Susav karki said:   9 years ago
Can anyone explain the third step?
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