Aptitude  Surds and Indices  Discussion
Discussion Forum : Surds and Indices  General Questions (Q.No. 8)
8.
1^{ }  +  1  +  1  = ? 
1 + x^{(b  a)} + x^{(c  a)}  1 + x^{(a  b)} + x^{(c  b)}  1 + x^{(b  c)} + x^{(a  c)} 
Answer: Option
Explanation:
Given Exp. = 

=  x^{a}  +  x^{b}  +  x^{c} 
(x^{a} + x^{b} + x^{c})  (x^{a} + x^{b} + x^{c})  (x^{a} + x^{b} + x^{c}) 
=  (x^{a} + x^{b} + x^{c}) 
(x^{a} + x^{b} + x^{c}) 
= 1.
Discussion:
24 comments Page 2 of 3.
Franklin Emeka said:
8 years ago
I am not understanding this. Any of them can explain me?
Favour said:
8 years ago
I do not understand any of them.
Achitsa said:
9 years ago
First solve the denominator using LCM the answer you get. Find its reciprocal.
Akshita Tank said:
9 years ago
Can anybody explain the question in easier way?
KazirangaUniv said:
9 years ago
From the second step:
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
x^a(x^a+x^b+x^c)^2+x^b(x^a+x^b+x^c)^2+x^c(x^a+x^b+x^c)^2/(x^a+x^b+x^c)^3
Then take (x^a+X^b+x^c)^2 common from numerator and denominator and cut them both from top and bottom. Then we get step 3.
Shekhar kushwaha said:
9 years ago
What if x = 0?
Abhijeet singh said:
1 decade ago
In the second line just take the LCM. and make the adjustment accordingly.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Its very simple try it on paper itself.
You guys will get the answer.
Thank you.
Anagha said:
1 decade ago
How do you solve the second step? Really confusing, please do it the long way so we can understand.
Sagar said:
1 decade ago
The second step is derived from first step by multiplying numerator & denominator of each of the 3 components with x^a, x^b & x^c respectively.
Arshad said:
1 decade ago
I did not understood second step from last.
Can you please explain in detail(only last two steps)
How do you consider x^a+x^b+x^c in numerator ?(x^a+x^b+x^c/x^a+x^b+x^c)
Can you please explain in detail(only last two steps)
How do you consider x^a+x^b+x^c in numerator ?(x^a+x^b+x^c/x^a+x^b+x^c)
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