Discussion :: Surds and Indices - General Questions (Q.No.3)
10(0.48z) = 10(2 x 0.70) = 101.40
0.48z = 1.40| Fazila said: (Nov 10, 2010) | |
| I think its something different method. | |
| Vignesh said: (Sep 26, 2011) | |
| This not the different one, as like a to the power m whole to the power of n=a to the power of m*n. | |
| Rajesh said: (Jan 20, 2012) | |
| Its very Simple. If Base Values are equal of both side than power's are equal. | |
| Adeyemi Raphael said: (Mar 5, 2012) | |
| Why do both side have to divided, not addtion, subtraction or mutplication to get final answer? | |
| Sagar said: (Jun 10, 2012) | |
| It is very easy to solve if you know Logarithm. Step1: Zlog(10^0.48)=2log(10^0.70) Step2: ZX0.48=2X0.70 (Log10=1) Step3: Z= 2.9 |
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| Roseline Aderonke said: (Nov 7, 2013) | |
| The workings are well understood once it is strictly followed step by step. | |
| Sanjay said: (Aug 18, 2014) | |
| What is the appropriate meaning of 2^0.5? | |
| Nego said: (Aug 2, 2015) | |
| I'm a bit confused about this. Why is the y2 not (0.70*0.70), rather its (2*0.70)? | |
| Tulasi said: (Sep 10, 2015) | |
| 10^0.48 = x //given. 10^0.7 = y //given. x^z = (10^0.7)^2. Since (a^m)^n = a^(m*n) we get, (10^0.48)^z = 10^(z*0.48) and (10^0.7)^2 = 10^(0.7*2). Now, 10^(0.48*z) = 10^(0.7*2). Since bases are equal, equating powers we get: z*0.48 = 0.7*2. z = 140/48. z = 2.9166 which is approximately 2.9. |
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| Kumar Arpit said: (Oct 11, 2015) | |
| That seems correct to me. I think this is the correct way. | |
| Thiyaguaxrev4Fvtr said: (May 26, 2016) | |
| How to get the answer? Please explain me. | |
| Jaichu said: (Mar 7, 2017) | |
| Please explain me. 0.48z = 1.40. z =140/48. How could they multiply it? |
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| Aniket Gaikwad said: (Apr 22, 2017) | |
| Thanks @Tulasi. | |
| Akhila said: (Jun 14, 2018) | |
| @Jaichu. For both nums decimal at the same place. So, a decimal can be removed. |
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| Jesophat said: (Feb 1, 2019) | |
| 48/100 = 0.48z =1.4z. | |
| Naman said: (Feb 17, 2020) | |
| I cannot understand it. | |
| Monisha Mohanan said: (Sep 19, 2021) | |
| X^ z = y ^ 2 [10^ .048]^z = [10 ^0.70]^2 Taking log on both sides, Log [10^ .048]^z = log [10 ^0.70]^2 Log a^b^c = c log a^ b And similarly c log a^b = c*b log a Z log10^ .048 = 2 log 10 ^0.70 Z * .48 log 10 = 2 * 0.70 log 10 .48 z = 1.4 here log 10 = 1. Z = 1.4 /.48. For easy calculation multiplying it by 100, Z = 140/48 = 2.9. |
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