### Discussion :: Surds and Indices - General Questions (Q.No.3)

Fazila said: (Nov 10, 2010) | |

I think its something different method. |

Vignesh said: (Sep 26, 2011) | |

This not the different one, as like a to the power m whole to the power of n=a to the power of m*n. |

Rajesh said: (Jan 20, 2012) | |

Its very Simple. If Base Values are equal of both side than power's are equal. |

Adeyemi Raphael said: (Mar 5, 2012) | |

Why do both side have to divided, not addtion, subtraction or mutplication to get final answer? |

Sagar said: (Jun 10, 2012) | |

It is very easy to solve if you know Logarithm. Step1: Zlog(10^0.48)=2log(10^0.70) Step2: ZX0.48=2X0.70 (Log10=1) Step3: Z= 2.9 |

Roseline Aderonke said: (Nov 7, 2013) | |

The workings are well understood once it is strictly followed step by step. |

Sanjay said: (Aug 18, 2014) | |

What is the appropriate meaning of 2^0.5? |

Nego said: (Aug 2, 2015) | |

I'm a bit confused about this. Why is the y2 not (0.70*0.70), rather its (2*0.70)? |

Tulasi said: (Sep 10, 2015) | |

10^0.48 = x //given. 10^0.7 = y //given. x^z = (10^0.7)^2. Since (a^m)^n = a^(m*n) we get, (10^0.48)^z = 10^(z*0.48) and (10^0.7)^2 = 10^(0.7*2). Now, 10^(0.48*z) = 10^(0.7*2). Since bases are equal, equating powers we get: z*0.48 = 0.7*2. z = 140/48. z = 2.9166 which is approximately 2.9. |

Kumar Arpit said: (Oct 11, 2015) | |

That seems correct to me. I think this is the correct way. |

Thiyaguaxrev4fvtr said: (May 26, 2016) | |

How to get the answer? Please explain me. |

Jaichu said: (Mar 7, 2017) | |

Please explain me. 0.48z = 1.40. z =140/48. How could they multiply it? |

Aniket Gaikwad said: (Apr 22, 2017) | |

Thanks @Tulasi. |

Akhila said: (Jun 14, 2018) | |

@Jaichu. For both nums decimal at the same place. So, a decimal can be removed. |

Jesophat said: (Feb 1, 2019) | |

48/100 = 0.48z =1.4z. |

Naman said: (Feb 17, 2020) | |

I cannot understand it. |

Monisha Mohanan said: (Sep 19, 2021) | |

X^ z = y ^ 2 [10^ .048]^z = [10 ^0.70]^2 Taking log on both sides, Log [10^ .048]^z = log [10 ^0.70]^2 Log a^b^c = c log a^ b And similarly c log a^b = c*b log a Z log10^ .048 = 2 log 10 ^0.70 Z * .48 log 10 = 2 * 0.70 log 10 .48 z = 1.4 here log 10 = 1. Z = 1.4 /.48. For easy calculation multiplying it by 100, Z = 140/48 = 2.9. |

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