Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 7)
7.
| If x = | 3 + 1 | and y = | 3 - 1 | , then the value of (x2 + y2) is: |
| 3 - 1 | 3 + 1 |
Answer: Option
Explanation:
| x = | (3 + 1) | x | (3 + 1) | = | (3 + 1)2 | = | 3 + 1 + 23 | = 2 + 3. |
| (3 - 1) | (3 + 1) | (3 - 1) | 2 |
| y = | (3 - 1) | x | (3 - 1) | = | (3 - 1)2 | = | 3 + 1 - 23 | = 2 - 3. |
| (3 + 1) | (3 - 1) | (3 - 1) | 2 |
x2 + y2 = (2 + 3)2 + (2 - 3)2
= 2(4 + 3)
= 14
Discussion:
45 comments Page 4 of 5.
SAMART BOY said:
1 decade ago
(2 + 3)2 + (2 - 3)2
= 2(4 + 3) ?
Can you explain?
= 2(4 + 3) ?
Can you explain?
Skrn said:
10 years ago
The question I got didn't have a root 3 value. Thanks.
Anjani said:
1 decade ago
We can do help from the equation (x2+y2)=(x+y)2-2xy;
Naomi Mwamba said:
4 years ago
Can someone clearly explain this in step by step?
(3)
Gopi said:
1 decade ago
The answer is to its formula (x+y)^2=x^2+y^2+2xy.
Sinthu said:
8 years ago
I couldn't understand. How is it possible?
(1)
Bhavesh Joshi said:
1 decade ago
Is there any shortcut method to solve ?
KARTHI said:
9 years ago
How to solve this problem logically?
Naren said:
8 years ago
Here, 2(x^2+y^2) = (x+y)^2+(x+y)^2.
Gaurav said:
1 decade ago
Asnwer to this seems to be '-10'.
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