Aptitude - Square Root and Cube Root - Discussion

Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 7)
7.
If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:
3 - 1 3 + 1
10
13
14
15
Answer: Option
Explanation:

x = (3 + 1) x (3 + 1) = (3 + 1)2 = 3 + 1 + 23 = 2 + 3.
(3 - 1) (3 + 1) (3 - 1) 2

y = (3 - 1) x (3 - 1) = (3 - 1)2 = 3 + 1 - 23 = 2 - 3.
(3 + 1) (3 - 1) (3 - 1) 2

x2 + y2 = (2 + 3)2 + (2 - 3)2

   = 2(4 + 3)

   = 14

Discussion:
45 comments Page 1 of 5.

Pavan Kumar said:   2 years ago
The value of √3 is 1.732. By applying this, we will get the answer.
(5)

Bhushan said:   6 years ago
x2 + y2 = (2 + √3)2 + (2 - √3)2.
= (4+2*2*√3+3) + (4 - 2*2*√3+3),
= (4+3) + (4+3),
= 2(4+3).
(5)

Jamshaid said:   3 years ago
@All.

Here, as whatever power of 1, it remains 1, simply;
(3)^1/2 +1 = (4)^1/2 = 2;
(3)^1/2 - 1 = (2)^1/2,
Thereby X = (2)^1/2 & Y = 1/(2)^1/2,
X^2 = 2 & Y^2 = 1/2.
Ans 2.5.
(3)

Naomi Mwamba said:   4 years ago
Can someone clearly explain this in step by step?
(3)

Chandrakala Rajput said:   2 years ago
Using , (x+y)^2 = x^2 +y^2 -2xy

So, x^2 +y^2 = (x+y) ^2 - 2xy ---> (I)

(X+y) = (√3 + 1) /(√3 - 1) + (√3 - 1) /(√3 + 1).

On taking LCM,
(X+y) = {(√3 + 1)^2 +(√3 - 1)^2}/(√3 - 1)(√3 +1).

(X+y) =(3+1-2√3 +3+1-2√3) /[(√3) ^2 - 1^2].

(X+y) = 8/(3-1),
(X+y) = 8/2,
(x+y) = 4.

Now, XY = {(√3 + 1) /(√3 - 1)} * {(√3 - 1) /(√3 + 1)},
XY = 1.

Now putting values of (X+y) & XY in equation (I)
x^2 + y^2 = (x+y) ^2 - 2xy ---> (I)
x^2 + y^2 = (4) ^2 - 2,
x^2 + y^2 = 16 - 2,
x^2 + y^2 = 14.

Answer is 14.
(1)

Sinku said:   8 years ago
x2+y2=(x-y)2+2xy, can we use this formula?

Anyone explain me.
(1)

Jayshree said:   10 years ago
Hello, I just didn't understand how is 3+1+2√3/2 = 2+√3.

Please explain.
(1)

Sakthi said:   1 decade ago
Root 3 -> 1.732.

1.732+1=2.732.
1.732-1=0.732.

2.732/0.732=3.7322.
0.732/2.732=0.2679.

(3.7322)^2=13.929 & (0.2679)^2=0.0192.

Add 13.929+0.0192=13.9482 is near by 14.

So answer is 14.
Are you clear now friends.
(1)

Vikas said:   1 decade ago
Could understand how {(3+2)/(3-2) }*{ (3+2)/(3+2)/(3+2)} = (3+2)^2/ (3-2), isn't it should be (3+2)^2/(3^2-1^2)? Please inform me asap.

Chotu said:   1 decade ago
(a+b)2+(a-b)2 = 2(a2+b2).

Here a = 2 =>a2 = 4; b = 3^(1/2) =>b2 = 3.

=>2(4+3).

=>2(7).

=>14.

I think this is the correct one because this is the model of rationalization. If this is not the correct answer please explain.

How would you get the answer as 2?


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