Aptitude - Square Root and Cube Root - Discussion

Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 7)
7.
If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:
3 - 1 3 + 1
10
13
14
15
Answer: Option
Explanation:

x = (3 + 1) x (3 + 1) = (3 + 1)2 = 3 + 1 + 23 = 2 + 3.
(3 - 1) (3 + 1) (3 - 1) 2

y = (3 - 1) x (3 - 1) = (3 - 1)2 = 3 + 1 - 23 = 2 - 3.
(3 + 1) (3 - 1) (3 - 1) 2

x2 + y2 = (2 + 3)2 + (2 - 3)2

   = 2(4 + 3)

   = 14

Discussion:
45 comments Page 2 of 5.

Gopi said:   1 decade ago
The answer is to its formula (x+y)^2=x^2+y^2+2xy.

Abhirup said:   10 years ago
The answer to this question is correct. They have just step-jumped.

Animesh said:   10 years ago
Use "(x^2+y^2) = (x+y)^2-2xy".

Here xy = 1;

Here just put the values of x and y and you can get the answer which is 14.

Bhavesh Kirange said:   10 years ago
@Jayshree.

3+1 = 4 so it becomes, 4+2√3/2.

Here take 2 common and it comes (2(2+√3))/2 = 2+√3.

Skrn said:   10 years ago
The question I got didn't have a root 3 value. Thanks.

KARTHI said:   9 years ago
How to solve this problem logically?

Deepak Gehlot said:   9 years ago
This is wrong solution.

Pranay Patil said:   9 years ago
Can anyone explain me why can't we solve x and y individually to get x^2 = 4 and y^2 = 1/4? So to get x^2 +y^2 = 17/4.

Shudipta Baruah said:   9 years ago
This is correct: 14

x = (3 + 1) x (3 + 1) = (3 + 1)2
= 3 + 1 + 23 = 2 + 3.
(3 - 1) (3 + 1) (3 - 1) 2.

y = (3 - 1) x (3 - 1) = (3 - 1)2 = 3 + 1 - 23 = 2 - 3.
(3 + 1) (3 - 1) (3 - 1) 2,
x2 + y2 = (2 + 3)2 + (2 - 3)2,
= 2(4 + 3),
= 14.

Kalesha said:   9 years ago
(2 + 3) 2 + (2 - 3) 2.
2 (4 + 3).

How can anyone explain this?


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