Aptitude - Square Root and Cube Root - Discussion

Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 7)
7.
If x = 3 + 1 and y = 3 - 1 , then the value of (x2 + y2) is:
3 - 1 3 + 1
10
13
14
15
Answer: Option
Explanation:

x = (3 + 1) x (3 + 1) = (3 + 1)2 = 3 + 1 + 23 = 2 + 3.
(3 - 1) (3 + 1) (3 - 1) 2

y = (3 - 1) x (3 - 1) = (3 - 1)2 = 3 + 1 - 23 = 2 - 3.
(3 + 1) (3 - 1) (3 - 1) 2

x2 + y2 = (2 + 3)2 + (2 - 3)2

   = 2(4 + 3)

   = 14

Discussion:
45 comments Page 2 of 5.

Jessi said:   1 decade ago
x = 3*2+1/3-1 = 9+1/2 = 10/2 = 5.

y = 3*2-1/3+1 = 9-1/4 = 8/4 = 2.

The use the formula x2+y2 = 5*2+2*2 = 10+4 = 14.

Animesh said:   10 years ago
Use "(x^2+y^2) = (x+y)^2-2xy".

Here xy = 1;

Here just put the values of x and y and you can get the answer which is 14.

Pranay Patil said:   9 years ago
Can anyone explain me why can't we solve x and y individually to get x^2 = 4 and y^2 = 1/4? So to get x^2 +y^2 = 17/4.

Bhushan said:   6 years ago
x2 + y2 = (2 + √3)2 + (2 - √3)2.
= (4+2*2*√3+3) + (4 - 2*2*√3+3),
= (4+3) + (4+3),
= 2(4+3).
(5)

Bhavesh Kirange said:   10 years ago
@Jayshree.

3+1 = 4 so it becomes, 4+2√3/2.

Here take 2 common and it comes (2(2+√3))/2 = 2+√3.

Ram said:   8 years ago
(2 + 3) 2 + (2 - 3) 2.

Explanation:
7+4root3+3+4-root3+3.
+4root3-4root3 cancel.

After that,

4+3+4+3 = 14.

Mohit said:   1 decade ago
Can any buddy help me to understand this problem solution in a simple and detail way.

Jayshree said:   10 years ago
Hello, I just didn't understand how is 3+1+2√3/2 = 2+√3.

Please explain.
(1)

Tank Mayur B. said:   1 decade ago
This is wrong solution .
because: ((a+b)/(a-b))*((a+b)/(a+b))=(a+b)2/(a2 + b2)

Jay said:   1 decade ago
Who got 2 as the correct answer? That's what I had and I'm sure I am right!


Post your comments here:

Your comments will be displayed after verification.