Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 13)
13.
A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
22
23
24
26
Answer: Option
Explanation:

Let the number of hens be x and the number of cows be y.

Then, x + y = 48 .... (i)

  and 2x + 4y = 140      x + 2y = 70 .... (ii)

Solving (i) and (ii) we get: x = 26, y = 22.

The required answer = 26.

Discussion:
67 comments Page 3 of 7.

Ranjan said:   6 years ago
Thanks all for explaining.

Afadmin said:   6 years ago
It can be solved by;

Total legs/2 - total head = total no of 4 legs animal.

= 140/2 - 48.
= 70 - 48 = 22 four legs animal,

Total 48. So 26 two legs animal means hens here.

Devan mavani said:   7 years ago
Short cut

Total legs/2 - total head = total no of 4 legs animal.

= 140/2 - 48.
= 70 -48 = 22 four legs animal,

Total 48. So 26 two legs animal means hens here.

DEEKSHANT UPADHYAY said:   7 years ago
48*4=192, 192-140=52÷2=26.

Cow=26, Hens=22.

Jai prakash said:   7 years ago
Well said, thanks @Shubham Yadav.

Riya said:   7 years ago
How come 140? Please explain.

Pushpa said:   7 years ago
Thanks @Sheeraz.

Shivu said:   7 years ago
Number of legs/2- head= value of 4 legs animals.

Shubham yadav said:   7 years ago
2 legs of formula= 2H - L/2.
Solve = 2 * 48 - 140/2
= 96 - 70
= 26.

Archita yadav said:   7 years ago
140/2 = 70,
70-48 = 22 (number of cows).
48-22 = 26 (number of hens).


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