Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 13)
13.
A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
Answer: Option
Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 .... (i)
and 2x + 4y = 140 
x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
Discussion:
67 comments Page 7 of 7.
Kaushlendra singh said:
1 decade ago
Let no.of hens = x.
So no.of cows = 48-x.
Therefore,
2x + 4*(48-x) = 140.
=> -2x = 140 - 192.
=> -2x = -52.
=> x = 26.
So no.of cows = 48-x.
Therefore,
2x + 4*(48-x) = 140.
=> -2x = 140 - 192.
=> -2x = -52.
=> x = 26.
Dhanalakshmi said:
1 decade ago
How x=26 and y=22 are coming?
Sk.Gopinath Siva said:
1 decade ago
They asked only for number of hens?
Sarthak said:
1 decade ago
Why haven't they count the head and feet of the man?
It should be:-
1+x+y = 48.
x+y = 47 ---- (1).
And 2+2x+4y = 140.
=> 2x+4y = 138 ---- (2).
By solving no.of hens (x) is 25.
It should be:-
1+x+y = 48.
x+y = 47 ---- (1).
And 2+2x+4y = 140.
=> 2x+4y = 138 ---- (2).
By solving no.of hens (x) is 25.
Deepi said:
1 decade ago
Hens have 2 legs and cows have 4 legs. So in-order to calculate number of hens and cows take as 2x+4y.
Srinu said:
1 decade ago
Can anyone tell me, how 2x and 4y are comming?
Jyothi said:
1 decade ago
Any short cut?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers