Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Answer: Option
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 
x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Discussion:
75 comments Page 5 of 8.
Selvi said:
1 decade ago
Please explain me, how to solve (i) & (ii) and how get x=100 & y=80?
Ramesh.Mariyada said:
9 years ago
Exactly I have the same doubt as same as @Nandhakumar.
Can anyone help us?
Can anyone help us?
Manish Kumar said:
1 decade ago
I couldn't get how we solve both equation please make it clear by multiply.
Gurpreet said:
1 decade ago
I didn't understand Solving (i) and (ii) we get: x = 100, why = 80. How?
Naidu said:
8 years ago
Why we have to change the signs could anyone please explain?
Sylvester said:
5 years ago
If 2A=B, Also A=2B.
A=80, B=40, in other words: A=40*2=80.
A=80, B=40, in other words: A=40*2=80.
(2)
Tuan Ossen said:
8 years ago
I don't understand, Please explain me with proper guidance.
Pratham said:
5 years ago
Hello, can you please explain the last step i.e x=100 y=80?
(3)
Basheerbi said:
1 decade ago
I can't understand the prasu explanation tell me clearly.
Idhaa said:
10 years ago
2 has come because there are two rooms in the question.
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