Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
20
80
100
200
Answer: Option
Explanation:

Let the number of students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

     and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100 , y = 80.

The required answer A = 100.

Discussion:
75 comments Page 4 of 8.

Vinshashee said:   1 decade ago
When 20 students sent from B to A,

Then A become twice then of B.

Thats The Reason We take 2 in the second step.

Jayashri said:   5 years ago
I disagree, if A is double the number of B.

How can 100 be the answer?

As B is 60 if we double it we get 160.
(5)

Sundar said:   1 decade ago
Assume x,y

x-a, y-b

10 students from b-a. So x-b,then y+b

Now doubled

2(y-20) then both equation solved.

Rama said:   1 decade ago
If you don't mine, somebody please explain this in clear cut. First of all I can't understand the question.

JOEPAUL said:   3 years ago
Then the number of students in A is double the number of students in B. This is because 2 (y-20).
(4)

Hello said:   6 years ago
Where is Ramesh? The one who explained the previous question very simply in this same chapter.
(1)

Naveena said:   9 years ago
Friends you are doing upto x and why values. But we have to double the A also comparing to B.

Jeet dutta said:   3 years ago
By Solving (i) and (ii) we get: x = 100, y = 80.

The required answer A = 100.
(3)

Kavya said:   9 years ago
It is A which is double. So the equation should be 2 (x + 20) = y - 20. Right?

Prashant said:   1 decade ago
Assume maximum capacity of both side 100 and subtract 20 from it a:b = 100:80.


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