Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
20
80
100
200
Answer: Option
Explanation:

Let the number of students in rooms A and B be x and y respectively.

Then, x - 10 = y + 10      x - y = 20 .... (i)

     and x + 20 = 2(y - 20)      x - 2y = -60 .... (ii)

Solving (i) and (ii) we get: x = 100 , y = 80.

The required answer A = 100.

Discussion:
75 comments Page 4 of 8.

Tuan said:   8 years ago
I don't understand this, please explain me.

Sreeram said:   8 years ago
See guys first take. x+10=2(y-40).
Then it comes as x-2y=-60,
First eq is x-y=20,

Solve both.
X-y=20,
x-2y=-60,

Change signs/
We get;
x-y=20,
-x+2y=60,
Then we get y=80,
Substitute in eq 1,
We get x=100.

Geetha said:   8 years ago
Assume A= 70 and B= 50.

Then according to question 10 students from A will be transferred to B so now they are going to b equal.
A=60 and B=60,
And if we transfer 20 students from B to A,
It's going to be A=80 and B=40 I.e A is double of B,
So why can't D answer be 80.

Shanthini said:   8 years ago
Friends I'll say one simple logic. If "is " is given after A then you must consider as A =. So as per question if we see means A is double the number of students in b.

So (x+20) =2 (y-20).

Akshay said:   8 years ago
Nice explanation, Thanks @Manojkumar.

Shiv Mohan Sharma said:   8 years ago
Explain how to solve equ.1 and equ.2?

Koteswararao chimmili said:   9 years ago
If 10 students are sent from A to B,then the number of students in each room is the same
a-10 = b+10 ; ---- (1)

If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B.
a+20 = 2(b -20); ---- (2) ( suppose A=10,B=5 that means A=2B then 10=10 )

Equation 1

a-10 = b+10.
a-b = 20.

Equation 2

a+20 = 2(b-20)
a+20 = 2b -40
a-2b = -60.


Solving equation 1 and 2
a-b = 20
a-2b = -60 (-a+2b = +60)
_____________.
b = 80

b is substitute in equation 1
a - b = 20
a = 20 + b
a = 20 + 80
a = 100

The answer is a = 100

Suman said:   9 years ago
Well explained @Tamil.

Srividya said:   9 years ago
Friends as the question had given that A is doubled then why we doubled B? Can anyone explain this problem in another process?

Manojkumar said:   9 years ago
I know everyone understood the first part, but in the second part, some might find difficult to understand why we are doubling in why part rather than the x part. Here is my view.

Read the question very very slowly.

Here they told, "If 20 candidates are sent from B to A, then the number of students in A is double the number in B". So x+20 = 2 (y - 20).

So for those who argue it should be 2 (x + 20) = y - 20, then the question would be below.

"If 20 candidates are sent from B to A, then the number of students in A is doubled (the remain details about B would have been ignored).

I hope it clear your doubts.
(1)


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