Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Answer: Option
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Discussion:
75 comments Page 4 of 8.
Tuan said:
8 years ago
I don't understand this, please explain me.
Sreeram said:
8 years ago
See guys first take. x+10=2(y-40).
Then it comes as x-2y=-60,
First eq is x-y=20,
Solve both.
X-y=20,
x-2y=-60,
Change signs/
We get;
x-y=20,
-x+2y=60,
Then we get y=80,
Substitute in eq 1,
We get x=100.
Then it comes as x-2y=-60,
First eq is x-y=20,
Solve both.
X-y=20,
x-2y=-60,
Change signs/
We get;
x-y=20,
-x+2y=60,
Then we get y=80,
Substitute in eq 1,
We get x=100.
Geetha said:
8 years ago
Assume A= 70 and B= 50.
Then according to question 10 students from A will be transferred to B so now they are going to b equal.
A=60 and B=60,
And if we transfer 20 students from B to A,
It's going to be A=80 and B=40 I.e A is double of B,
So why can't D answer be 80.
Then according to question 10 students from A will be transferred to B so now they are going to b equal.
A=60 and B=60,
And if we transfer 20 students from B to A,
It's going to be A=80 and B=40 I.e A is double of B,
So why can't D answer be 80.
Shanthini said:
8 years ago
Friends I'll say one simple logic. If "is " is given after A then you must consider as A =. So as per question if we see means A is double the number of students in b.
So (x+20) =2 (y-20).
So (x+20) =2 (y-20).
Akshay said:
8 years ago
Nice explanation, Thanks @Manojkumar.
Shiv Mohan Sharma said:
8 years ago
Explain how to solve equ.1 and equ.2?
Koteswararao chimmili said:
9 years ago
If 10 students are sent from A to B,then the number of students in each room is the same
a-10 = b+10 ; ---- (1)
If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B.
a+20 = 2(b -20); ---- (2) ( suppose A=10,B=5 that means A=2B then 10=10 )
Equation 1
a-10 = b+10.
a-b = 20.
Equation 2
a+20 = 2(b-20)
a+20 = 2b -40
a-2b = -60.
Solving equation 1 and 2
a-b = 20
a-2b = -60 (-a+2b = +60)
_____________.
b = 80
b is substitute in equation 1
a - b = 20
a = 20 + b
a = 20 + 80
a = 100
The answer is a = 100
a-10 = b+10 ; ---- (1)
If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B.
a+20 = 2(b -20); ---- (2) ( suppose A=10,B=5 that means A=2B then 10=10 )
Equation 1
a-10 = b+10.
a-b = 20.
Equation 2
a+20 = 2(b-20)
a+20 = 2b -40
a-2b = -60.
Solving equation 1 and 2
a-b = 20
a-2b = -60 (-a+2b = +60)
_____________.
b = 80
b is substitute in equation 1
a - b = 20
a = 20 + b
a = 20 + 80
a = 100
The answer is a = 100
Suman said:
9 years ago
Well explained @Tamil.
Srividya said:
9 years ago
Friends as the question had given that A is doubled then why we doubled B? Can anyone explain this problem in another process?
Manojkumar said:
9 years ago
I know everyone understood the first part, but in the second part, some might find difficult to understand why we are doubling in why part rather than the x part. Here is my view.
Read the question very very slowly.
Here they told, "If 20 candidates are sent from B to A, then the number of students in A is double the number in B". So x+20 = 2 (y - 20).
So for those who argue it should be 2 (x + 20) = y - 20, then the question would be below.
"If 20 candidates are sent from B to A, then the number of students in A is doubled (the remain details about B would have been ignored).
I hope it clear your doubts.
Read the question very very slowly.
Here they told, "If 20 candidates are sent from B to A, then the number of students in A is double the number in B". So x+20 = 2 (y - 20).
So for those who argue it should be 2 (x + 20) = y - 20, then the question would be below.
"If 20 candidates are sent from B to A, then the number of students in A is doubled (the remain details about B would have been ignored).
I hope it clear your doubts.
(1)
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