Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 2)
2.
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Answer: Option
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 
x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
Discussion:
75 comments Page 3 of 8.
Saurya said:
6 years ago
Thank all for explaining.
Kaleem said:
6 years ago
Thank you all.
Nagesh v said:
7 years ago
Thank for you answer @Ash.
Garry said:
7 years ago
Accroding to last condtion, It should be 2(x+20).
Geethanjali said:
7 years ago
Simple to understand Thank you @Hiranmoy.
Srinu said:
7 years ago
Nice explanation. Thanks.
Hiranmoy said:
7 years ago
X-10 = y+10.
X-y = 10+10.
=20 (i).
Then, x+20 = 2(y-20)
x-2y = 40
x-y = 2x40
x-y = 80 (ii).
Now adding (i) &(ii) we get 20+80 = 100.
X-y = 10+10.
=20 (i).
Then, x+20 = 2(y-20)
x-2y = 40
x-y = 2x40
x-y = 80 (ii).
Now adding (i) &(ii) we get 20+80 = 100.
Naidu said:
8 years ago
Why we have to change the signs could anyone please explain?
Tuan Ossen said:
8 years ago
I don't understand, Please explain me with proper guidance.
Temmy said:
8 years ago
How did they get the y=80?
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