Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 12)
12.
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?
Answer: Option
Explanation:
Let total number of children be x.
| Then, x x | 1 | x = | x | x 16  x = 64. |
| 8 | 2 |
 Number of notebooks = |
1 | x2 = |  |
1 | x 64 x 64 |  |
= 512. |
| 8 | 8 |
Discussion:
42 comments Page 5 of 5.
Ganesh said:
1 decade ago
@Mohit.
Same thing for you as well. Question and explanation are correct in Indiabix. First you understand and then comment.
Same thing for you as well. Question and explanation are correct in Indiabix. First you understand and then comment.
Prabhath said:
9 years ago
Case I:.
Number of children = C.
Number of books each child got = C/8.
So, total number of books B = C * C/8 = C^2/8.
Case II:.
Number of children is reduced to half = C/2.
Now the number of books each child gets = 16.
So, total number of books B = C/2 * 16 = 8C.
In both cases the Total number of books distributed are same.
So, C^2/8 = 8C.
Solving we get C = 64.
That gives.
Total number of books B = 8C = C^2/8 = 512.
This is the conventional method. For short-cuts refer the above given explanation.
Number of children = C.
Number of books each child got = C/8.
So, total number of books B = C * C/8 = C^2/8.
Case II:.
Number of children is reduced to half = C/2.
Now the number of books each child gets = 16.
So, total number of books B = C/2 * 16 = 8C.
In both cases the Total number of books distributed are same.
So, C^2/8 = 8C.
Solving we get C = 64.
That gives.
Total number of books B = 8C = C^2/8 = 512.
This is the conventional method. For short-cuts refer the above given explanation.
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