Aptitude - Simplification - Discussion

heya..
here v vil calculate the total no. of buks in 1st condtion and den in 2nd condition and eqate dem..
acc. to 1st condition,
Total no. of buks= no. of buks to 1 student have * no.of student
let no. of students= x
no. of buks 1 student have= 1/8*x
hence total no. of buks=(1/8*x)*x ............(1)

acc. to 2nd condition,
no. of students=x/2
no. of buks 1 student have=16
hence total no. of buks=(x/2)*16 .............(2)
nw from (1)&(2) equation,
(1/8*x)*x=(x/2)*16
on solving we get x=64
nw you can calculate total no. of buks from any 1 or 2nd equation
frm 1st equation
total no. of buks=(1/8*x)*x
=(1/8*64)*64
=512
thnks..I hope now every1 can get logic..!!

We should know that Total no of the book is same for both the case. It's just that the no. Of books received by each std is different.

For full strength of STDs.
Book received individually = 1/8 of x.
where x = total students.
Total no. of books = 1/8 of x * x.

For half strength of stds;
We know total std is x, so half std means x/2.
Total books = total std * 16 ( book received individually).
We know for the second case total std is half(x/2) so;
Total books = x/2 * 16.

So now we know that total no. Of books is same for both the case.
Thus equating the equ for total no of books:
1/8 of x *x = x/2 * 16,
We get x = 64,
Hence the substituting x, we get 512 as the total no of books.

Heya..
here we will calculate the total no. of buks in 1st condtion and den in 2nd condition and eqate dem..
acc. to 1st condition,
Total no. of buks= no. of buks to 1 student have * no.of student
let no. of students= x
no. of buks 1 student have= 1/8*x
hence total no. of buks=(1/8*x)*x ............(1)

acc. to 2nd condition,
no. of students=x/2
no. of buks 1 student have=16
hence total no. of buks=(x/2)*16 .............(2)
nw from (1)&(2) equation,
(1/8*x)*x=(x/2)*16
on solving we get x=64
nw you can calculate total no. of buks from any 1 or 2nd equation
frm 1st equation
total no. of buks=(1/8*x)*x
=(1/8*64)*64
=512

Let number of children be x.

Then it is given that 1 child got 1/8 of no of children i.e.1/8 of x which means x/8.

Now if 1 child got x/8 then total number of notebooks

Or x children got (x/8) * x = x^2/8, Eqn --->1.

In second case number of children is half i.e. x/2.

1 child got 16 then x/2 got = 16 * x/2 = 8x, Eqn --->2.

Now we have 2 expressions.

1) 8x.

2) x^2/8.

Both are equal since both represent the total number of notebooks.

Equating them.

8x = x^2/8.

x^2 = 64x.

x = 64.

Put this value in anyone 1 or 2.

The total number of notebooks = 8 * 64 = 512.

Case I:.

Number of children = C.
Number of books each child got = C/8.
So, total number of books B = C * C/8 = C^2/8.

Case II:.

Number of children is reduced to half = C/2.
Now the number of books each child gets = 16.
So, total number of books B = C/2 * 16 = 8C.

In both cases the Total number of books distributed are same.

So, C^2/8 = 8C.

Solving we get C = 64.

That gives.

Total number of books B = 8C = C^2/8 = 512.

This is the conventional method. For short-cuts refer the above given explanation.

Let no. of children= x

The third line of the problem says:
Had the no. of children been half, means- x/2, then each child would have got 16 notebooks means- x/2=16.

So, x=32(these are only half of the children), then total children= 32x2= 64 children.

The second line of the problem says:

The no. of notebooks each child(i.e 1 child) got was 1/8 of the no. of children, means-
1/8 of 64= 8 notebooks,

So, if 1 child got 8 notebooks, then 64 children got 64x8 = 512 total notebooks.

If class is half student get half books compared to full class.

So full class strength is 32*8 = 256.

And total number of books distributed are 8192.

As simple as that first time looking and wrong question in Indiabix.

And look people are giving explanations that are totally vague what they are doing is equating half strength one side with full strength another side.

Before typing such explanations one should be clear in his own calculations.

Let, total no of students = x,
books allotted to each is = x/8,
Total no of books is = x * x/8 = x^2/8.

Now, is total students is halved i.e = x/2.
Books will be allotted to each is = (x/2)/8 = x/16.
Which is given = 16.
x/16 = 16
x = 256 ---> (i).

Now, the total number of books = (x^2)/8.
Putting the value of x gives 8192.

Correct me guys. if I am wrong.

@ALL.

Each student has 16 books i.e total students are 16*8=128
It is said students are halved i.e we to double it 2*126=256>> actual number of students.

Each student gets books equal to 1/8 of total class strength 256/8=32>> actual number of books each student gets.

Total books distributed are 32*256=8192.

Tell me if I am wrong.

Let no of children be=y.

Total books distributed in case 1 would be=y*(y/8) i.e. no. of children*book got by each child.

total books distributed in case 2 would be=(y/2)*16 i.e.no. of children in case 2 (half of y)*(book received by each child which is given as 16).

equate case 1=case2.

You will get no. of children y=64.