Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 12)
12.
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?
Answer: Option
Explanation:
Let total number of children be x.
| Then, x x | 1 | x = | x | x 16  x = 64. |
| 8 | 2 |
 Number of notebooks = |
1 | x2 = |  |
1 | x 64 x 64 |  |
= 512. |
| 8 | 8 |
Discussion:
42 comments Page 3 of 5.
Jay negi said:
9 years ago
512/ 16 = 32.
It 's half of the total no. 32 * 2=64.
512/64 = 8 it's dived to total no of children & 64 * 1/8.
It 's half of the total no. 32 * 2=64.
512/64 = 8 it's dived to total no of children & 64 * 1/8.
Prabhath said:
9 years ago
Case I:.
Number of children = C.
Number of books each child got = C/8.
So, total number of books B = C * C/8 = C^2/8.
Case II:.
Number of children is reduced to half = C/2.
Now the number of books each child gets = 16.
So, total number of books B = C/2 * 16 = 8C.
In both cases the Total number of books distributed are same.
So, C^2/8 = 8C.
Solving we get C = 64.
That gives.
Total number of books B = 8C = C^2/8 = 512.
This is the conventional method. For short-cuts refer the above given explanation.
Number of children = C.
Number of books each child got = C/8.
So, total number of books B = C * C/8 = C^2/8.
Case II:.
Number of children is reduced to half = C/2.
Now the number of books each child gets = 16.
So, total number of books B = C/2 * 16 = 8C.
In both cases the Total number of books distributed are same.
So, C^2/8 = 8C.
Solving we get C = 64.
That gives.
Total number of books B = 8C = C^2/8 = 512.
This is the conventional method. For short-cuts refer the above given explanation.
Ganesh said:
1 decade ago
@Mohit.
Same thing for you as well. Question and explanation are correct in Indiabix. First you understand and then comment.
Same thing for you as well. Question and explanation are correct in Indiabix. First you understand and then comment.
Mohit bansal said:
1 decade ago
If class is half student get half books compared to full class.
So full class strength is 32*8 = 256.
And total number of books distributed are 8192.
As simple as that first time looking and wrong question in Indiabix.
And look people are giving explanations that are totally vague what they are doing is equating half strength one side with full strength another side.
Before typing such explanations one should be clear in his own calculations.
So full class strength is 32*8 = 256.
And total number of books distributed are 8192.
As simple as that first time looking and wrong question in Indiabix.
And look people are giving explanations that are totally vague what they are doing is equating half strength one side with full strength another side.
Before typing such explanations one should be clear in his own calculations.
Sibhi said:
1 decade ago
As per the above calculations made by others if the total number of students are 64, then half the students when multiplied with 1/8th of them will be equal to 4.
But in question it is give as 16. All the above answers are wrong. Total number of students will be 256 and total number of books will be 8192 books.
But in question it is give as 16. All the above answers are wrong. Total number of students will be 256 and total number of books will be 8192 books.
Satyapravallika. said:
1 decade ago
@Swapna.
I couldn't understand your logic. Please explain me.
According to the question, if no.of children are halved then each student gets 16 books.
Then how we will equate both?
I couldn't understand your logic. Please explain me.
According to the question, if no.of children are halved then each student gets 16 books.
Then how we will equate both?
Swapna said:
1 decade ago
No of children = (1/2)x = 16.
=> x = 32,
So the no.of children is 32 then the no of notebooks is:
32x16 = 512.
=> x = 32,
So the no.of children is 32 then the no of notebooks is:
32x16 = 512.
Gugan said:
1 decade ago
@Lakshmi.
Both the conditions are related to Total no of books. Hence they are equated.
Both the conditions are related to Total no of books. Hence they are equated.
Lakshmi said:
1 decade ago
Why should we equate those 2 conditions?
Salil Shete said:
1 decade ago
Case 1:
X is no of student.
No of books to each student= X/8.
therefore,
Total no of books = X * X/8.
Case 2:
If no of student is half = X/2 .
Each student will get 16 books.
Total no of books = 16*X/2.
Case 1 and 2.
X*X/8 = 16*X/2.
X = 64.
Case 2 : Total no of books = 16 * 64/2 = 512.
X is no of student.
No of books to each student= X/8.
therefore,
Total no of books = X * X/8.
Case 2:
If no of student is half = X/2 .
Each student will get 16 books.
Total no of books = 16*X/2.
Case 1 and 2.
X*X/8 = 16*X/2.
X = 64.
Case 2 : Total no of books = 16 * 64/2 = 512.
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