Aptitude - Simplification - Discussion
Discussion Forum : Simplification - General Questions (Q.No. 4)
4.
If a - b = 3 and a2 + b2 = 29, find the value of ab.
Answer: Option
Explanation:
2ab = (a2 + b2) - (a - b)2
= 29 - 9 = 20
ab = 10.
Discussion:
107 comments Page 7 of 11.
Gyanika said:
9 years ago
Can somebody please solve this question.
a - b = 1, 2a + 20 = b. Then a, b is?
a - b = 1, 2a + 20 = b. Then a, b is?
Tanim Ehsan said:
9 years ago
If a + b = 13 and ab = 3 then (a+2b)^2-5b^2 = ?
Simplify the solution.
Simplify the solution.
Sonali said:
9 years ago
a-b = 3, a2+b2=29, ab =?
(a-b)2 = a2+b2-2ab
2ab = (a2+b2)-(a-b)2
ab = 29-9/2
= 20/2 = 10 Ans.
(a-b)2 = a2+b2-2ab
2ab = (a2+b2)-(a-b)2
ab = 29-9/2
= 20/2 = 10 Ans.
Bonjor said:
9 years ago
I would be grateful if anyone answers this question.
If a-b=4 and ab=60 then find the value of a+b.
I found that the answer is + or - 16 what is + or -? Please tell me.
If a-b=4 and ab=60 then find the value of a+b.
I found that the answer is + or - 16 what is + or -? Please tell me.
Harsh singh said:
9 years ago
Yes @Bonjor.
(a+b)2 = (a-b)2+4ab,
(a+b)2 = 256,
a+b = +-16.
+-16 is the answer.
(a+b)2 = (a-b)2+4ab,
(a+b)2 = 256,
a+b = +-16.
+-16 is the answer.
Yaswanth chinni said:
9 years ago
2ab = (a2 + b2) - (a - b)2.
= 29 - 9 = 20,
ab = 10.
= 29 - 9 = 20,
ab = 10.
Venkat@rockzzzz said:
9 years ago
(a-b)^2 = a^2+b^2-2ab.
2ab = a^2+b^2-(a-b)^2,
= 29-3^2,
= 29-9,
2ab = 20.
ab =10.
2ab = a^2+b^2-(a-b)^2,
= 29-3^2,
= 29-9,
2ab = 20.
ab =10.
Venkat@rockzzzz said:
9 years ago
(a-b)^2 = a^2+b^2-2ab.
2ab = a^2+b^2-(a-b)^2,
= 29-3^2,
= 29-9,
2ab = 20.
ab =10.
2ab = a^2+b^2-(a-b)^2,
= 29-3^2,
= 29-9,
2ab = 20.
ab =10.
Sandilya said:
9 years ago
Yes @Harsh Singh.
(a+b)2 = (a-b)2+4ab,
(a+b)2 = 256,
a+b = +-16.
+-16 is the answer.
(a+b)2 = (a-b)2+4ab,
(a+b)2 = 256,
a+b = +-16.
+-16 is the answer.
Mangesh said:
9 years ago
Please give the answer of (a-b) =4 ab=52.25 then a^2 * b^2 = ?
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