# Aptitude - Simplification - Discussion

Discussion Forum : Simplification - General Questions (Q.No. 7)

7.

One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,50,000 as total savings, how much has he saved in Public Provident Fund ?

Answer: Option

Explanation:

Let savings in N.S.C and P.P.F. be Rs. *x* and Rs. (150000 - *x*) respectively. Then,

1 | x = |
1 | (150000 - x) |

3 | 2 |

x |
+ |
x |
= 75000 | |

3 | 2 |

5x |
= 75000 | |

6 |

x = |
75000 x 6 | = 90000 |

5 |

Savings in Public Provident Fund = Rs. (150000 - 90000) = Rs. 60000

Discussion:

27 comments Page 1 of 3.
Ram said:
1 year ago

1/3 A=1/2 B and A=3B/2.

A+B=1, 50,000.

3B/2 +B =1,50,000,

5B/2 = 1,50,000,

B = 3,00,000/5 =60, 000.

B = 60,000.

A+B=1, 50,000.

3B/2 +B =1,50,000,

5B/2 = 1,50,000,

B = 3,00,000/5 =60, 000.

B = 60,000.

(14)

R k senthil raajan said:
3 years ago

Ratio is the best method to solve.

Take the lcm for 2 and 3 is 6.

Therefore A s part is 3 B s part is 2.

Total part is 5.

Divide the total amount /5.

One part is equal to 30000.

B's part 2*30000 = 60000.

Take the lcm for 2 and 3 is 6.

Therefore A s part is 3 B s part is 2.

Total part is 5.

Divide the total amount /5.

One part is equal to 30000.

B's part 2*30000 = 60000.

(5)

Rekha said:
3 years ago

Thank you @Sanjay.

Angothu Vamshi said:
5 years ago

Solution:

1/3n(national savings certificate) = 1/2p(public provident fund).

n/p = 3/2,

n:p = 3:2.

So, Total savings/(ratio total),

150000/5 = 30000,

Then, p = 2(30000).

= 60000.

1/3n(national savings certificate) = 1/2p(public provident fund).

n/p = 3/2,

n:p = 3:2.

So, Total savings/(ratio total),

150000/5 = 30000,

Then, p = 2(30000).

= 60000.

Vineela said:
5 years ago

N/3 = P/2.

Therefore, N = 3/2P.

Given N+P = 1,50,000,

3/2P+P = 1,50,000,

5/2P = 1,50,000,

Therefore, P = 1,50,000 * 2/5 = 60,000.

Therefore, N = 3/2P.

Given N+P = 1,50,000,

3/2P+P = 1,50,000,

5/2P = 1,50,000,

Therefore, P = 1,50,000 * 2/5 = 60,000.

(1)

Sukhman said:
5 years ago

Let his savings in NSF be = x.

Let his savings in PPF be = y.

ATQ

X/3=y/2.

On solving yhis we get

2x =3y,

2/3x =y,

Now

X+y = 150000,

Putting the value of y as solved above.

X+2/3x = 150000,

X = 90000,

Y = 150000-90000 = 60000.

Let his savings in PPF be = y.

ATQ

X/3=y/2.

On solving yhis we get

2x =3y,

2/3x =y,

Now

X+y = 150000,

Putting the value of y as solved above.

X+2/3x = 150000,

X = 90000,

Y = 150000-90000 = 60000.

(1)

Ashutosh giri said:
6 years ago

How 75000 came?

Alish said:
6 years ago

x---->NSF.

y---->PPF.

x/3 = y/2 (as said in question ) --> (1)

x + y = 1,50,000 ( Total) --> (2)

From (1); we have, x=3/2 y ( put that in 2nd equation and directly we give the value of y which is PPF).

3/2 y + y = 1,50,000,

5/2 y = 1,50,000,

y = 1,50,000 * 2/5,

y = 60,000.

y---->PPF.

x/3 = y/2 (as said in question ) --> (1)

x + y = 1,50,000 ( Total) --> (2)

From (1); we have, x=3/2 y ( put that in 2nd equation and directly we give the value of y which is PPF).

3/2 y + y = 1,50,000,

5/2 y = 1,50,000,

y = 1,50,000 * 2/5,

y = 60,000.

(1)

Pritam said:
6 years ago

x/3+x/2= 1,50,000(total saving),

5x/6= 1,50,000.

x= 1,50,000*6/5 = 1,80,000.

ppf = x/2 so ppf may be 1,80,000/2 = 90,000.

5x/6= 1,50,000.

x= 1,50,000*6/5 = 1,80,000.

ppf = x/2 so ppf may be 1,80,000/2 = 90,000.

Nilesh Sonje said:
6 years ago

Let,

3 parts of NSC + 2 parts of PPF = 150000.

Total 5 parts = 150000,

1 part = 30000,

2 parts of PPF = 60000.

3 parts of NSC + 2 parts of PPF = 150000.

Total 5 parts = 150000,

1 part = 30000,

2 parts of PPF = 60000.

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