Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 4 of 12.
Mangesh said:
7 years ago
P=13900
A=14%
B=11%
So,total SI= 3508.
Hence we need to fine out B scheme.
Use option given 1st option is 6400,
6400*2 year*11%÷100=1408,
And remaining intrest is 3508-1408=2100,
Now A scheme,
13900-6400=7500,
7500*2year*14%÷100=2100.
A=14%
B=11%
So,total SI= 3508.
Hence we need to fine out B scheme.
Use option given 1st option is 6400,
6400*2 year*11%÷100=1408,
And remaining intrest is 3508-1408=2100,
Now A scheme,
13900-6400=7500,
7500*2year*14%÷100=2100.
(1)
Ismail khan said:
1 decade ago
pin/100 + (13900-p)in/100=3508 where p is principle
i is interest rate and n is no.of years
p(28/100)+(13900-p)22/100=3508
28p+13900*22-22p=3508*100
28p-22p+305800=350800
6p=45ooo
p=7500
13900-7500=6400
i is interest rate and n is no.of years
p(28/100)+(13900-p)22/100=3508
28p+13900*22-22p=3508*100
28p-22p+305800=350800
6p=45ooo
p=7500
13900-7500=6400
Phani Kumar said:
1 decade ago
Here the shortcut for this kind of problems.
P1 = ((100*I) - (P*T*R2))/(difference of R1 and R2). And then find P2 by:
P2 = P-P1.
Here,
P = 13900.
P1 = Part1;
P2 = Part2;
I = 3508;
T = 2;
R1 = 14;
R2 = 11;
P1 = ((100*I) - (P*T*R2))/(difference of R1 and R2). And then find P2 by:
P2 = P-P1.
Here,
P = 13900.
P1 = Part1;
P2 = Part2;
I = 3508;
T = 2;
R1 = 14;
R2 = 11;
Vinod said:
1 decade ago
Suppose total simple interest of A & B is 13900*25%(14%+11%) =3475, but in problem total interest for 2 years is 3508, difference amount is Rs.33/-,can some one explain me, why this differnce has come ?
Srini said:
1 decade ago
@Vinod
You cannot take 25% directly from Principal since money is divided into two parts, so that diff is there in your calculation
Now see, 7500 x 14% + 6400 x 11% in 2 years will give you 3508.
You cannot take 25% directly from Principal since money is divided into two parts, so that diff is there in your calculation
Now see, 7500 x 14% + 6400 x 11% in 2 years will give you 3508.
Anuj said:
6 years ago
With alligation method.
B = 11%.
A = 14%.
Calculate Rate for 1 year on 100*1754/13900*1 = 12.61%.
1754 is one-year int.
mean is 12.61%.
then 14%-12.61% = 1.38%.
12.61-11 = 1.61.
1.38/3*13900 = 6400.
B = 11%.
A = 14%.
Calculate Rate for 1 year on 100*1754/13900*1 = 12.61%.
1754 is one-year int.
mean is 12.61%.
then 14%-12.61% = 1.38%.
12.61-11 = 1.61.
1.38/3*13900 = 6400.
Eeswar kumar said:
1 decade ago
By using simple formula [(I*100-P*R2)/R1-R2] = P2.
Here p = Total amount shared between A & B as P = P1+P2.
I = Total interest; R1 = P1's rate of interest, R2 = P2's rate of interest.
Here p = Total amount shared between A & B as P = P1+P2.
I = Total interest; R1 = P1's rate of interest, R2 = P2's rate of interest.
Bushra said:
9 years ago
What is the answer for the question?
A farmer has a rectangular garden plot surrounded by 200ft of the fence. Find the length and width of the garden if its area is 2400ft2.
A farmer has a rectangular garden plot surrounded by 200ft of the fence. Find the length and width of the garden if its area is 2400ft2.
Umesh gandla said:
7 years ago
x x 14 x 2 + (13900 - x) x 11 x 2 = 3508.
100 100
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
100 100
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
(2)
Madhu said:
8 years ago
@Phani Kumar
Can you please solve using the formula you stated?
i.e P1= {(100*1)-(PTR2)} / (R1-R2),
P2=P-P1.
Please anyone help me with this solution.
Can you please solve using the formula you stated?
i.e P1= {(100*1)-(PTR2)} / (R1-R2),
P2=P-P1.
Please anyone help me with this solution.
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