Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 2)
2.
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
| Then, |  |
x x 14 x 2 |  |
+ | |
(13900 - x) x 11 x 2 | |
= 3508 |
| 100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Video Explanation: https://youtu.be/Xi4kU9y6ppk
Discussion:
115 comments Page 3 of 12.
Naveen be cool said:
9 years ago
A = 14 * 2 yrs.
B = 11 * 2 yrs.
Now you'll get 28, & 22.
=> 28 + 22 = 50 * 3508 * 2 = 350800.
Now you need to find the amount of B = 22 * 13900 = 305800.
So. 350800 - 305800 = 45000 .
28 - 22 difference is = 6.
Now 45000/6 = 7500.
=> 13900 - 7500 = 6400.
Then the value of A is 7500 and B is 6400.
B = 11 * 2 yrs.
Now you'll get 28, & 22.
=> 28 + 22 = 50 * 3508 * 2 = 350800.
Now you need to find the amount of B = 22 * 13900 = 305800.
So. 350800 - 305800 = 45000 .
28 - 22 difference is = 6.
Now 45000/6 = 7500.
=> 13900 - 7500 = 6400.
Then the value of A is 7500 and B is 6400.
Sravs said:
6 years ago
Let calculate SI for 14% per anum si = 13900*1*14/100 = 1946,
Caluculate si for 11% per anum si = 13900 * 1 * 11/100 = 1529,
Given intrerest for 2 year so 3508/2 = 1754 p.a.
By using alligation:
1956-1754 = 192
1754 - 1529 = 225.
Tatio;-B:A = 192 : 225.
Sum of B = 13900 * 192/417 = 6400.
Caluculate si for 11% per anum si = 13900 * 1 * 11/100 = 1529,
Given intrerest for 2 year so 3508/2 = 1754 p.a.
By using alligation:
1956-1754 = 192
1754 - 1529 = 225.
Tatio;-B:A = 192 : 225.
Sum of B = 13900 * 192/417 = 6400.
(2)
Aditi said:
1 decade ago
C let us assume that principle invested in a is x
& b be y
total amt invested is 13900
so x+y=13900 or y=13900-x rit-----1
foorming quad eq. of simple int.
x*14*2/100 + y*11*2/100 = 3508 i=prt/100
or 28x/100+22y/100=3508
28x+22y=350800
substitution of y frm 1
28x+22(13900-x)=350800 now solve.
& b be y
total amt invested is 13900
so x+y=13900 or y=13900-x rit-----1
foorming quad eq. of simple int.
x*14*2/100 + y*11*2/100 = 3508 i=prt/100
or 28x/100+22y/100=3508
28x+22y=350800
substitution of y frm 1
28x+22(13900-x)=350800 now solve.
Teja said:
1 decade ago
See, it is given that both a&b together combinedly having principal amount of 13,900 for two years having si of 3508.
Now by adding both schemes si's with the total si given for two years by using formula
si = p*t*r/100.
By considering scheme b = 13,900-a,
We can find investment on b scheme.
Now by adding both schemes si's with the total si given for two years by using formula
si = p*t*r/100.
By considering scheme b = 13,900-a,
We can find investment on b scheme.
Azly said:
9 years ago
We can solve this using simultaneous equations. Here we go!
Total interest for 2 years - 3508.
Then for a year - 3508/2 = 1754.
Assume investment in A scheme as x and B as Y.
14/100 * x + 11/100 * y = 1754 --------> 1st eqn
x + y = 13900 -------> 2nd eqn.
Solve this. You will get the answer.
Total interest for 2 years - 3508.
Then for a year - 3508/2 = 1754.
Assume investment in A scheme as x and B as Y.
14/100 * x + 11/100 * y = 1754 --------> 1st eqn
x + y = 13900 -------> 2nd eqn.
Solve this. You will get the answer.
Venu sabbani said:
9 years ago
13900 is then two parts 14 * 2 and 11 * 2.
Then 28 and 22(scheme A and scheme B difference is 6%).
28% of 13900 = 3892.
3892 -> given amount, then3892 - 3508 = 384.
Two schemes difference is 6%(28 - 22).
6% = 384.
Sum 100% =?
Then cross multiplication 384 * 100/6 = 6400 is the answer.
Then 28 and 22(scheme A and scheme B difference is 6%).
28% of 13900 = 3892.
3892 -> given amount, then3892 - 3508 = 384.
Two schemes difference is 6%(28 - 22).
6% = 384.
Sum 100% =?
Then cross multiplication 384 * 100/6 = 6400 is the answer.
Sreelatha said:
7 years ago
C let us assume that principle invested in a is x.
& b be y.
The total amt invested is 13900,
so x+y=13900 or y=13900-x,
by using formula i=ptr/100,
x*14*2/100 + y*11*2/100,
= 28x/100+22y/100=3508,
28x+22y=350800,
Substitution of y frm 1
28x+22(13900-x) = 350800 now solve.
& b be y.
The total amt invested is 13900,
so x+y=13900 or y=13900-x,
by using formula i=ptr/100,
x*14*2/100 + y*11*2/100,
= 28x/100+22y/100=3508,
28x+22y=350800,
Substitution of y frm 1
28x+22(13900-x) = 350800 now solve.
(2)
Insaan said:
1 decade ago
@ Pp depu
See, 28x/100 + (13900 - x)* 22 / 100 = 3508
= 28x/100 + 305800 - 22x /100 = 3508
take 100 lcm
28x + 305800 - 22x/100 = 3508
or 28x + 305800 - 22x = 350800
or 28x + 305800 - 22x - 350800 = 0
0r 28x - 45000 - 22x = 0
or 6x - 45000 = 0
or 6x = 45000
x = 7500
See, 28x/100 + (13900 - x)* 22 / 100 = 3508
= 28x/100 + 305800 - 22x /100 = 3508
take 100 lcm
28x + 305800 - 22x/100 = 3508
or 28x + 305800 - 22x = 350800
or 28x + 305800 - 22x - 350800 = 0
0r 28x - 45000 - 22x = 0
or 6x - 45000 = 0
or 6x = 45000
x = 7500
Sourav Kalal said:
4 years ago
Let me solve it in a simple way.
13900 X 11% = 1529 (They asked for B whose interest is 11%).
2 YR = 3508
1 YR = 1754,
EXTRA INTERST = 1754-1529 = 225.
That extra interest nothing but 14%-11%=3%,
3% = 225,
100% = 7500,
13900-7500 = 6400,
13900 X 11% = 1529 (They asked for B whose interest is 11%).
2 YR = 3508
1 YR = 1754,
EXTRA INTERST = 1754-1529 = 225.
That extra interest nothing but 14%-11%=3%,
3% = 225,
100% = 7500,
13900-7500 = 6400,
(73)
Dhilip said:
8 years ago
It is a PTR/100 formula total SI is given we find amount invested in B so subtract x from p here x is an amount invested and p total amount. Two different scheme so we add two amount and the SI is placed other side by the formula
SI=P*R*T/100.
SI=P*R*T/100.
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