Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 9)
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
3.6%
4.5%
5%
6%
None of these
Answer: Option
Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).

725 x R x 1 + 362.50 x 2R x 1 = 33.50
100 100 x 3

(2175 + 725) R = 33.50 x 100 x 3

(2175 + 725) R = 10050

(2900)R = 10050

R = 10050 = 3.46
2900

Original rate = 3.46%

Discussion:
97 comments Page 7 of 10.

Abdul rawoof khanday said:   1 decade ago
It is very important to understand question relate question with your daily life eg I deposited etc etc.

Kiran said:   2 years ago
@All.

I Have 1 doubt. 1st He will be lent for 8 months or 1 year? Anyone, please explain me in detail.
(12)

Sudhanshu said:   1 decade ago
In the question the SI for the second loan should be calculated for 4 months and not the whole year.

Sai krishna said:   1 decade ago
Please explain solution clearly with step by step process. How we got 1/3 as time in second case?

Nijin said:   4 years ago
Shouldn't we change the number of years as 8/12 and 3/12 instead of 1? Anyone, please clarify.
(18)

SEKHAR said:   4 years ago
Why don't we take it like this?

SI = (725 * 8 * R/100 * 2) + (362.50 * 4 * 2R/100 * 2).

Rachana M R said:   4 years ago
@Nijin.

12 months =1 year,
4 months =?
On cross multiplication, we get 4/12 = 1/3.
(7)

Asif said:   1 decade ago
It should be:

725*r*8/(12*100) + 362.5*2r*4/(12*100) = 33.50.

R will be = 4.62%

Syed said:   7 years ago
How to calculate 725*R*1/ 100 and how come 2175?

Please solve it Step By Step.

Akram said:   2 years ago
Why 2R/3 is coming in the second S.I formula, it should be 1/3 only,right?
(3)


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