Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 9)
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Answer: Option
Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).
![]() |
![]() |
725 x R x 1 | ![]() |
+ | ![]() |
362.50 x 2R x 1 | ![]() |
= 33.50 |
100 | 100 x 3 |
(2175 + 725) R = 33.50 x 100 x 3
(2175 + 725) R = 10050
(2900)R = 10050
![]() |
10050 | = 3.46 |
2900 |
Original rate = 3.46%
Discussion:
97 comments Page 10 of 10.
Ugyen dema said:
4 years ago
How 2175 * 725? Please explain this.
(1)
Sandeep said:
9 years ago
Why r is taken as 2r? Explain.
Tom and Jerry said:
12 months ago
How come 2175? Please explain.
(10)
Sujeet said:
8 years ago
How, 2175 has come?
(1)
Muneer said:
10 years ago
How it comes 2175?
@hmed said:
9 years ago
Why we take 2175?
Sindu said:
6 years ago
3 * 725 = 2175.
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