Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 9)
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
3.6%
4.5%
5%
6%
None of these
Answer: Option
Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).

725 x R x 1 + 362.50 x 2R x 1 = 33.50
100 100 x 3

(2175 + 725) R = 33.50 x 100 x 3

(2175 + 725) R = 10050

(2900)R = 10050

R = 10050 = 3.46
2900

Original rate = 3.46%

Discussion:
97 comments Page 1 of 10.

Abhiruchi said:   1 decade ago
How

725 x R x 1
-------------
100

become 2175

Shubhra said:   1 decade ago
(725 x R x 1 /100) + (362.50 x 2R x 1 /100 x 3 ) = 33.50

(725 x 1 /100 + 362.50 x 2 /100 x 3) R = 33.50

(725 x 3 + 725 / 100 x 3) R = 33.50

(2175 + 725 ) R = 33.50 x 100 x 3

(2900) R = 10050

R = 10050/2900

R = 3.46%

Tarun said:   1 decade ago
In question,just after 8 month,,principal change..725 only for 8 month..so its SI should b claculated only for 8 month and thn..for next 4 month the toatal amount(725+362.50) sholud consider as next 4 month principal..at rate 2R..

Meenakshie said:   1 decade ago
For the 8 month principal should be (725+362.50)=1087.50

Aakash said:   1 decade ago
After reading it carefully I got it Tarun.

The rate of interest which is twice in case of 362.50 is twice only for 362.50 and not for (725+ 362.50)/

Second thing ---> don't take this question as a single 1. See both the problems with different view.

Rs 725 is not taken back it is uniform through out the year.

Still any kind of queries are welcomed.

Supriya said:   1 decade ago
I think the correct solution is as follows:

1) consider P=725, R=r, n= 8 months
SI= [725*(8/12)*r]/100= 4.833r
Amount= SI+P
Amount= 4.833r+725
this amount will be principle for next step

2) P= (4.833r+725)+362.5 = 1087.5+4.833r
R= 2r, n=4 months

SI= [ (1087.5+4.883r)*(4/12)*2r]/100 = 33.5
solving this r= 4.529%

Is this solution correct....??
please suggest me..!!

Suman said:   1 decade ago
Let the original rate is r%, then new rate is 2r.
here original rate is for only 8 months i.e 2/3; new rate is for 4 month i.e 1/3year(s).
=>{(725*r*2)/(100*3)}+{(362.50*2r*1)/(100*3)}=33.50
=>4.8333333333r+2.4166666667r=33.50
=>7.25r=33.50
=>r=33.50/7.25
=>r=4.6206896552
i.e original rate=4.62%

Shashi said:   1 decade ago
The interest of Rs725 he had collect at the end of the year with the interest of 4 months of Rs 362.5 so calculate it &you will get the correct answer.

Mariam said:   1 decade ago
Suman answer is wrong. Because in question he lent the amt and doesnt paid it back. If he pays after 8 months we can consider it as 8/12. Explanation given to the answer is correct.

Satnam said:   1 decade ago
Here, original rate is for 1 year (s) ; the new rate is for only 4 months i.e. 1/3year (s).
Can anybody explain this line. How it becomes 1/3 ?


Post your comments here:

Your comments will be displayed after verification.