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Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 9)
Simple Interest
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
3.6%
4.5%
5%
6%
None of these
Answer: Option
Explanation:

Let the original rate be R%. Then, new rate = (2R)%.

Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).

725 x R x 1 + 362.50 x 2R x 1 = 33.50
100 100 x 3

(2175 + 725) R = 33.50 x 100 x 3

(2175 + 725) R = 10050

(2900)R = 10050

R = 10050 = 3.46
2900

Original rate = 3.46%

Discussion:
97 comments Page 10 of 10.
Nias said:   3 years ago
After 8 months means he is lent for the remaining 4 months within the year. In a simple way, someone can't lend for the previous time rather he lent for the future time.

Therefore, the result of 1/4 we can understand from this concept.
(7)
Kiran said:   2 years ago
@All.

I Have 1 doubt. 1st He will be lent for 8 months or 1 year? Anyone, please explain me in detail.
(12)
Akram said:   2 years ago
Why 2R/3 is coming in the second S.I formula, it should be 1/3 only,right?
(3)
Pranshi said:   2 years ago
Why we didn't take 8/12 instead of 1? Please explain me.
(20)
Prakash c said:   2 years ago
1st amount of 725 is considered as 1 year amount then 2nd part of the amount is considered as 4 months interest. Then we will give the perfect answer.
(1)
Tom and Jerry said:   12 months ago
How come 2175? Please explain.
(10)
Ayan said:   11 months ago
For 8 months take 2/3.
For 4 months take 1/3.

Then 725 * R * 2/100 * 3 + 362.50 * 2R * 1/100 * 3 = 4.62 approx. This is the correct solution.
(15)
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