Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 9)
9.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest?
Answer: Option
Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. 
year(s).
 |
 |
725 x R x 1 |  |
+ | |
362.50 x 2R x 1 | |
= 33.50 |
| 100 | 100 x 3 |
(2175 + 725) R = 33.50 x 100 x 3
(2175 + 725) R = 10050
(2900)R = 10050
| R = |
10050 | = 3.46 |
| 2900 |
Original rate = 3.46%
Discussion:
97 comments Page 4 of 10.
Neha said:
9 years ago
Anybody can explain that why we add 1 year = remaining 4 months. I think it will be 1 year 4 month.
Secondly, after 8 months 362.50 is more.
So we must add 362.50 in 725 for remaining 4 months?
Secondly, after 8 months 362.50 is more.
So we must add 362.50 in 725 for remaining 4 months?
Mani said:
1 decade ago
after 8 months principle should be 725+362.50 but in answer he was write only 362.50 how will it come?
And original rate only 8 months so time=8/12 years but he was write 1 year. how is?
And original rate only 8 months so time=8/12 years but he was write 1 year. how is?
Mariam said:
1 decade ago
Suman answer is wrong. Because in question he lent the amt and doesnt paid it back. If he pays after 8 months we can consider it as 8/12. Explanation given to the answer is correct.
Kirti said:
10 years ago
Why it has been taken first for 1 year and after 8 years because in the question it has already mention that after 8 years he lended 362.50 and at the beginning he lended 725?
ANU said:
1 decade ago
This is how I did it.
[725*1*i/100]+[362.50*4/12*i/100] = 33.50.
7.25i+2.416i = 33.50.
9.66i = 33.50.
i = 33.50/9.66.
i = 3.46%.
Here I have taken i as rate of interest(R).
[725*1*i/100]+[362.50*4/12*i/100] = 33.50.
7.25i+2.416i = 33.50.
9.66i = 33.50.
i = 33.50/9.66.
i = 3.46%.
Here I have taken i as rate of interest(R).
Naga dheeraj said:
5 years ago
725 x R x 1 + 362.50 x 2R x 1 = 33.50.
100 100 x 3.
(2175 + 725) R = 33.50 x 100 x 3,
(2175 + 725) R = 10050,
(2900)R = 10050.
R = 10050 = 3.46.
2900.
Original rate = 3.46%.
100 100 x 3.
(2175 + 725) R = 33.50 x 100 x 3,
(2175 + 725) R = 10050,
(2900)R = 10050.
R = 10050 = 3.46.
2900.
Original rate = 3.46%.
Mukesh verma said:
1 decade ago
It is not specified in the the question.
1. What is original rate of interest whether it is rate of all the money involved or it is only for money other than 362.50 rupees?
1. What is original rate of interest whether it is rate of all the money involved or it is only for money other than 362.50 rupees?
Amith sourya said:
1 decade ago
The solution he given is wrong. Because for first case he took 8 months and for second month he took the remaining months i.e. 12-8 = 4. But he took in solution as 1 year.
Ab eth said:
3 years ago
Agee @Neha.
Because for 1 year we take 725 principal amount then it says 362.50 more after 8 months, for this reason, it must be 725 + 362.5 for the second principal.
Because for 1 year we take 725 principal amount then it says 362.50 more after 8 months, for this reason, it must be 725 + 362.5 for the second principal.
(26)
Vijay said:
1 decade ago
Hi,
In this question,for 8 months 750 with r%,remaining 362.5 with 2r% but he is doing for 1 year & 4 months,may be the answer is wrong ? what he explained.
In this question,for 8 months 750 with r%,remaining 362.5 with 2r% but he is doing for 1 year & 4 months,may be the answer is wrong ? what he explained.
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