Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Discussion:
174 comments Page 6 of 18.
NARENDRA said:
1 decade ago
SI1 = 815.
SI2 = 854.
DIFFERENCE = SI2-SI1.
D = 854-815.
D = 39.
FOR 3 YEARS = 3*39.
= 117.
SO NOW P = 815-117.
P = 698.
SI2 = 854.
DIFFERENCE = SI2-SI1.
D = 854-815.
D = 39.
FOR 3 YEARS = 3*39.
= 117.
SO NOW P = 815-117.
P = 698.
Padma said:
7 years ago
We can also solve in another way.
Si for 1 year = 854-815 = 39.
Si for 4 years = 39 * 4 = 156.
Principal = sum-interest.
= 854 - 156 = 698.
Si for 1 year = 854-815 = 39.
Si for 4 years = 39 * 4 = 156.
Principal = sum-interest.
= 854 - 156 = 698.
Suraj.D said:
9 years ago
Please tell me if we subtract 854- 815 we get principal+ s.I for 1 year. Then can we consider it only s.I for 1 year? Please explain me.
Shubham Mude said:
6 years ago
We can also use the below formula:
(A1*T2 - A2*T1) / (T2-T1)
= (815*4 - 854*3) / (4-3)
= (3260 - 2562) / 1
= 698.
Hence, the answer.
(A1*T2 - A2*T1) / (T2-T1)
= (815*4 - 854*3) / (4-3)
= (3260 - 2562) / 1
= 698.
Hence, the answer.
Stuti said:
1 decade ago
Hi.
There is a simple shortcut for solving this question.
P/Sum = A1n2-A2n1/n2-n1.
= 815*4-854*3/4-3.
= 3260-2562/1 = 698.
There is a simple shortcut for solving this question.
P/Sum = A1n2-A2n1/n2-n1.
= 815*4-854*3/4-3.
= 3260-2562/1 = 698.
Koishik mandal said:
8 years ago
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Hari said:
1 decade ago
I like this type of solutions thank you
I think this answer also
1year 854-815=39
3years 39*4=156
854-156=698
I think this answer also
1year 854-815=39
3years 39*4=156
854-156=698
Lelisa said:
7 years ago
4y-3y =1y so that 1y can be Rs. (854-815) Rs.39.
So, 3 years then 39 * 3 = 117.
So the principal is 815-117 =698.
So, 3 years then 39 * 3 = 117.
So the principal is 815-117 =698.
Pradeep said:
9 years ago
Let 1 yr int .....x.
3yr int.......3x.
4yr int........4x.
(P+4x) - (P+3x) = 854 - 815,
x = 39.
3yr int.......3x.
4yr int........4x.
(P+4x) - (P+3x) = 854 - 815,
x = 39.
Mahesh Narayankar said:
6 years ago
Let x=principal interest.
x+3*SI = 815.
x+4*Si = 854.
SI for 1 Year=854-815=39,
x+3*39=815,
x=815-117=698.
x+3*SI = 815.
x+4*Si = 854.
SI for 1 Year=854-815=39,
x+3*39=815,
x=815-117=698.
(1)
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