Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 1)
1.
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:
Answer: Option
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Discussion:
171 comments Page 5 of 18.
Vishnu said:
1 decade ago
To get a si of one year or it might be two years if it is two year we have to divide it by two si=3yrs -2yrs willl give u one year si why should we have to go to risk.
VarunRaj said:
1 decade ago
If we take for four years.
39*4 = 156.
854-156 = 698 is the answer.
If we take three years.
39*3 = 117.
815-117 = 698 the answer is same !
We can do both the way.
39*4 = 156.
854-156 = 698 is the answer.
If we take three years.
39*3 = 117.
815-117 = 698 the answer is same !
We can do both the way.
Sumit Singh said:
1 decade ago
815 ------ 854 (This value 39 increase in 1 year ).
So in four year 39*4/156.
This 156 is interest in four year.
So principle is equal to / 854-156 equal to 698.
So in four year 39*4/156.
This 156 is interest in four year.
So principle is equal to / 854-156 equal to 698.
Madhu said:
8 years ago
Basic formula of to find r% and p%.
When give two amounts and two years to find p formula,
(A1*T2-A2*T1)/T2-T1.
R% FORMULA.
(A2-A1)/(A1*T2-A2*T1).
When give two amounts and two years to find p formula,
(A1*T2-A2*T1)/T2-T1.
R% FORMULA.
(A2-A1)/(A1*T2-A2*T1).
Muskan said:
1 decade ago
Please give me the solution of this question.
A certain sum given on simple interest became double in 20 years. In how many years will it be 4 times.
A certain sum given on simple interest became double in 20 years. In how many years will it be 4 times.
Tanuja said:
9 years ago
Yeah, this is the very easy solution. But can you explain this method with some other examples?
Like 9 years SI is 657 and 5 years SI is 555 so then?
Like 9 years SI is 657 and 5 years SI is 555 so then?
Magesh said:
1 decade ago
For four years the interest is,
854-815 = 39.
39*4 = 156.
So 854-156 = 698.
It may simple one no need to apply any formulas here. Time waste one.
854-815 = 39.
39*4 = 156.
So 854-156 = 698.
It may simple one no need to apply any formulas here. Time waste one.
Venkatesh said:
1 decade ago
Gayathri thank you so much before that I want to say myself I am dull even though I understood you are explantion it is very clear keep it up.
NARENDRA said:
1 decade ago
SI1 = 815.
SI2 = 854.
DIFFERENCE = SI2-SI1.
D = 854-815.
D = 39.
FOR 3 YEARS = 3*39.
= 117.
SO NOW P = 815-117.
P = 698.
SI2 = 854.
DIFFERENCE = SI2-SI1.
D = 854-815.
D = 39.
FOR 3 YEARS = 3*39.
= 117.
SO NOW P = 815-117.
P = 698.
Padma said:
7 years ago
We can also solve in another way.
Si for 1 year = 854-815 = 39.
Si for 4 years = 39 * 4 = 156.
Principal = sum-interest.
= 854 - 156 = 698.
Si for 1 year = 854-815 = 39.
Si for 4 years = 39 * 4 = 156.
Principal = sum-interest.
= 854 - 156 = 698.
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