Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 10)
10.
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
Answer: Option
Explanation:
| Principal = Rs. |  |
100 x 5400 |  |
= Rs. 15000. |
| 12 x 3 |
Discussion:
31 comments Page 1 of 4.
Kannan said:
1 decade ago
Can you show me the work out sample for this i couldn't get it.
Anusha said:
1 decade ago
Can you please explain it clearly
Srinivas said:
1 decade ago
S.I=P*T*R/100
SIMPLE INTEREST=5400
T=3
R=12
THEREFORE P=S.I*100/T*R
=5400*100/12*3
=15000
SIMPLE INTEREST=5400
T=3
R=12
THEREFORE P=S.I*100/T*R
=5400*100/12*3
=15000
Sanna said:
1 decade ago
Let the principal amount be p
simple interest=p*n*r/100
so, p*3*12/100=Rs.5400
p*36/100=5400
p=5400*100/36
p=Rs.15000
Thus we can get the answer....
simple interest=p*n*r/100
so, p*3*12/100=Rs.5400
p*36/100=5400
p=5400*100/36
p=Rs.15000
Thus we can get the answer....
NAVEEN said:
1 decade ago
Can anybody expand this formula. SI = PTR/100.
Nimisha said:
1 decade ago
@Naveen
'p' is principle,
't' is time,
'n' is number of years and
'r' is rate of interest.
'p' is principle,
't' is time,
'n' is number of years and
'r' is rate of interest.
Ashik said:
1 decade ago
p=?
r=12%
t=3 yrs
p*t*r/100=s.i
p*3*12/100=5400
p*36=5400*100=540000
p=540000/36
p=15000
r=12%
t=3 yrs
p*t*r/100=s.i
p*3*12/100=5400
p*36=5400*100=540000
p=540000/36
p=15000
Anand said:
1 decade ago
I=(PRN)/100
Simple formulae.
Simple formulae.
Anusha said:
1 decade ago
Tell me logic's about this problems.
Debashree said:
1 decade ago
In 1 year interest is 5400/3=1800rs.
12rs interest in 100 rs principal.
Then 1800rs interest for (1800*100)/12=15000rs(answer).
12rs interest in 100 rs principal.
Then 1800rs interest for (1800*100)/12=15000rs(answer).
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