Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 5)
5.
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
3.6
6
18
Cannot be determined
None of these
Answer: Option
Explanation:

Let rate = R% and time = R years.

Then, 1200 x R x R = 432
100

12R2 = 432

R2 = 36

R = 6.

Video Explanation: https://youtu.be/TjjI4iRkzT0

Discussion:
62 comments Page 4 of 7.

Chandra Kiran.Baru said:   1 decade ago
P = 1200.
I = 432.
Time = r.
Rate = r%.

S.I = ptr\100.
432 = 1200*r*r\100.

R2 = 432\12.
R2 = 36 = 6.

Rajasekar said:   1 decade ago
How you could take the interest (R) and no of the years (R) both are same constant/Value as R?

RM Doubt said:   1 decade ago
It is not mention in the question that rate of interest and time duration both are equal.

Maleeha said:   8 years ago
I can't be understand how t= r? please help me to solve the question with simple method.

Anil said:   1 decade ago
Actually, I am unable to understand what the question is, can anyone please explain me.

Dunoo Michael said:   4 years ago
Looking at the question,

R = sI * 100/p * T.
R * R = 432*100/ 1200,
R * R = 36,
R = 6.
(2)

Sulthan shareef said:   3 years ago
1200 * R * R/100 = 432.
12R * R = 432,
R * R = 432/12,
R * R = 36,
R = 36/2,
R = 6.
(6)

Ganeshgoud said:   1 decade ago
R = (S.I*100/P*T).
S.I = 432;
P = 1200;
T = R;
R = 432*100/1200*R.
R2 = 36.
R = 6.

Mukesh said:   9 years ago
How can you say that?

Time (R) = Rate of Interest (R).

It may be different.

Zahid Hasan said:   5 years ago
I= prn/100,

So r=I * 100/pn, atq r=n=x (let),r=36/x as r=n x2=36, x=6.


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