Aptitude - Simple Interest - Discussion

Discussion Forum : Simple Interest - General Questions (Q.No. 5)
5.
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
3.6
6
18
Cannot be determined
None of these
Answer: Option
Explanation:

Let rate = R% and time = R years.

Then, 1200 x R x R = 432
100

12R2 = 432

R2 = 36

R = 6.

Video Explanation: https://youtu.be/TjjI4iRkzT0

Discussion:
62 comments Page 3 of 7.

Chandra Kiran.Baru said:   1 decade ago
P = 1200.
I = 432.
Time = r.
Rate = r%.

S.I = ptr\100.
432 = 1200*r*r\100.

R2 = 432\12.
R2 = 36 = 6.

Preethi said:   1 decade ago
Why here we take t=r?

Rajasekar said:   1 decade ago
How you could take the interest (R) and no of the years (R) both are same constant/Value as R?

RM Doubt said:   1 decade ago
It is not mention in the question that rate of interest and time duration both are equal.

MAHAVEER said:   9 years ago
The answer is D.

Because It is not mentioned in the question that rate of interest and time duration both are equal.

Brizelda said:   9 years ago
What is p?

Swa said:   9 years ago
R = 100 * si/p * t.
R^2 = 100 * 432/1200.
So 36, Here we are not taking T. Simply we took R as square because R = T.

Avana said:   9 years ago
So how about making T = x.
It will reach in a point of,
36 = r * x.
In order to make one as subject take the two latter as square and it will lead into 6.
r = 6,
x = 6,
r * x = 36,
6 * 6 = 36.

Rudragouda said:   9 years ago
Why we need to take R here is there any rule for that? Please tell me.

Geeta said:   9 years ago
Why we take replace of T?


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