Aptitude - Simple Interest - Discussion
Discussion Forum : Simple Interest - General Questions (Q.No. 5)
5.
Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
Answer: Option
Explanation:
Let rate = R% and time = R years.
| Then, |  |
1200 x R x R |  |
= 432 |
| 100 |
12R2 = 432
R2 = 36
R = 6.
Video Explanation: https://youtu.be/TjjI4iRkzT0
Discussion:
62 comments Page 2 of 7.
Dunoo Michael said:
5 years ago
Looking at the question,
R = sI * 100/p * T.
R * R = 432*100/ 1200,
R * R = 36,
R = 6.
R = sI * 100/p * T.
R * R = 432*100/ 1200,
R * R = 36,
R = 6.
(2)
Bhargav said:
5 years ago
I got the answer 18, can anyone please explain?
(2)
BANTI BISWAL said:
1 decade ago
Why we take R inplace of T ?
(1)
Ashima Singh said:
8 years ago
See the solution is:
Principle is-1200
Time:?
Rate :
Simple interest:432
Now we have to find Rate,
Now apply rate formula.
R=100/txsimple interest /principle.
R=100/t x 432/1200.
R=43200/1200.
R=6years.
Principle is-1200
Time:?
Rate :
Simple interest:432
Now we have to find Rate,
Now apply rate formula.
R=100/txsimple interest /principle.
R=100/t x 432/1200.
R=43200/1200.
R=6years.
(1)
Teja said:
9 years ago
@All.
First I too confused each subject has its own style of language. Here in the problem itself said r = t and asked interest so r placed here if they ask time means T-square.
First I too confused each subject has its own style of language. Here in the problem itself said r = t and asked interest so r placed here if they ask time means T-square.
(1)
Yousuf Mayuri said:
9 years ago
If Reena took Rs. 1200.
SI = P * R * T/100.
She paid of Rs. 432 at the end of the loan period.
Here, rate of interest is directly proportional to time.
P= 1200
SI= 432
R= ?
T=R
Therefore , SI = P * R * T/100.
432= 1200 * R * T=R/100,
432=1200 * R * R/100,
432=1200 * R^2/100,
432= 12 * R^2,
432/12 = R^2,
36 = R^2,
OR
R^ = 36.
Therefore, R = 6 Answer.
SI = P * R * T/100.
She paid of Rs. 432 at the end of the loan period.
Here, rate of interest is directly proportional to time.
P= 1200
SI= 432
R= ?
T=R
Therefore , SI = P * R * T/100.
432= 1200 * R * T=R/100,
432=1200 * R * R/100,
432=1200 * R^2/100,
432= 12 * R^2,
432/12 = R^2,
36 = R^2,
OR
R^ = 36.
Therefore, R = 6 Answer.
Mukesh said:
9 years ago
How can you say that?
Time (R) = Rate of Interest (R).
It may be different.
Time (R) = Rate of Interest (R).
It may be different.
Mahesh Babu said:
9 years ago
Here they given simple interest for as many years as the rate of interest.
So time =rate of interest so we take them as y.
They given our principal is Rs.1200,
S.I= P*T*R/100.
Here S.I=R.s 432,
Here Time=rate of interest,
432=1200*y*y/100.
432=12*y*y,
432\12=y*y,
y*y=36,
So y=6.
So Rate of interest =6%.
So time =rate of interest so we take them as y.
They given our principal is Rs.1200,
S.I= P*T*R/100.
Here S.I=R.s 432,
Here Time=rate of interest,
432=1200*y*y/100.
432=12*y*y,
432\12=y*y,
y*y=36,
So y=6.
So Rate of interest =6%.
Anusha said:
9 years ago
How we assume Rate (R) & Time (T) are equal values?
Maleeha said:
8 years ago
I can't be understand how t= r? please help me to solve the question with simple method.
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