Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 5)
5.
In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:
Answer: Option
Explanation:
| Quantity of milk = |  |
60 x | 2 |  litres = 40 litres. |
| 3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
| Then, milk : water = | |
40 | |
. |
| 20 + x |
| Now, | |
40 | |
= | 1 |
| 20 + x | 2 |
20 + x = 80
x = 60.
Quantity of water to be added = 60 litres.
Discussion:
147 comments Page 2 of 15.
Sukri said:
5 years ago
Initially we have 60lt in the ratio 2:1.
i.e: 40lt milk & 20lt water.
Think logically,
Our condition is to make the ratio as 1:2.
i.e: 40lt milk & 80lt water.
Then 40 : 80 it will become 1:2.
So, the required amount of water will be 80 - 20 (i.e: final quantity - initial quantity -> then we can get req amount of water to make the ratio as 1:2).
i.e: 40lt milk & 20lt water.
Think logically,
Our condition is to make the ratio as 1:2.
i.e: 40lt milk & 80lt water.
Then 40 : 80 it will become 1:2.
So, the required amount of water will be 80 - 20 (i.e: final quantity - initial quantity -> then we can get req amount of water to make the ratio as 1:2).
(1)
Shahzaib said:
6 years ago
In the tank we have 60 litter:
Case 1
For ratio 2:1
We have 40:20
Case 2
For ratio 1:2:
Now the thing is that as you can see from case 2 ratio which is 1:2 it means we have to twice the value of water and we not want to change milk quantity which is 1 so,
(2/3*60) + 20(from precious case 1 water ratio)
= 60.
We have used 2/3 from basic ratio formula.
Case 1
For ratio 2:1
We have 40:20
Case 2
For ratio 1:2:
Now the thing is that as you can see from case 2 ratio which is 1:2 it means we have to twice the value of water and we not want to change milk quantity which is 1 so,
(2/3*60) + 20(from precious case 1 water ratio)
= 60.
We have used 2/3 from basic ratio formula.
Kartik negi said:
1 decade ago
Let the ratio be 2x and 1x
add it to get,
2x+1x=60
3x=60
x=20
now,milk=2x20=40ltr.
and water=1x20=20ltr.
we know that something is added to water..
therefore,new ratio is 1:2 after adding the quantity of water
therefore,40/20+x=1/2 ( note that x=new quantity of water that is to be added)
cross multiply it and u will get the ans. =60
Hence proved.
add it to get,
2x+1x=60
3x=60
x=20
now,milk=2x20=40ltr.
and water=1x20=20ltr.
we know that something is added to water..
therefore,new ratio is 1:2 after adding the quantity of water
therefore,40/20+x=1/2 ( note that x=new quantity of water that is to be added)
cross multiply it and u will get the ans. =60
Hence proved.
Omkar said:
1 decade ago
Please correct if I am wrong.
The above problem can be rather simply solved by elimination of the Options:
Milk : 40litres.
Water: 20litres.
What value of water would you add to existing water so that it doubles compared to the quantity of milk (40 litres) present in the mixture : 20 + 60 = 80 (which is now double of 40)
Hence 60 litres.
The above problem can be rather simply solved by elimination of the Options:
Milk : 40litres.
Water: 20litres.
What value of water would you add to existing water so that it doubles compared to the quantity of milk (40 litres) present in the mixture : 20 + 60 = 80 (which is now double of 40)
Hence 60 litres.
Teja said:
5 years ago
M:W (initial mixture)
2:1
1:2(required).
Given total volume = 60ltrs.
As milk is not added we the ratio of milk need to be same in both the cases.
2*(1:2)=2:4(required).
2:1(initial).
4-1=3(difference in water in both cases).
2+1=total volume (60).
3-----> 60.
From this, we can say another 3 parts were added to get the required ratio.
2:1
1:2(required).
Given total volume = 60ltrs.
As milk is not added we the ratio of milk need to be same in both the cases.
2*(1:2)=2:4(required).
2:1(initial).
4-1=3(difference in water in both cases).
2+1=total volume (60).
3-----> 60.
From this, we can say another 3 parts were added to get the required ratio.
Madhur Nanhorya said:
11 months ago
Here, we can't just add different quantities of water.
So from the first case we got milk = 40 litres and water = 20 litres, now to make the ratio from 2:1 to 1:2.
So, the Amount of milk in the new mixture = 2 x milk in the old mixture = 2 x 40 litres = 80 litres, so the difference in water quantities = 80 - 20 = 60 litres.
So from the first case we got milk = 40 litres and water = 20 litres, now to make the ratio from 2:1 to 1:2.
So, the Amount of milk in the new mixture = 2 x milk in the old mixture = 2 x 40 litres = 80 litres, so the difference in water quantities = 80 - 20 = 60 litres.
(11)
Krishna said:
1 decade ago
The original ratio is 2:1.
That means 40 liters milk and 20 liters water.
We have to add x liters of water so that ratio becomes 1:2.
Here milk quantity doesn't change.
So in 1:2 ratio.
1 part is equal to 40liters.
2 parts-------------------?
80liters.
So the quantity of water to be added is 80-20=60.
That means 40 liters milk and 20 liters water.
We have to add x liters of water so that ratio becomes 1:2.
Here milk quantity doesn't change.
So in 1:2 ratio.
1 part is equal to 40liters.
2 parts-------------------?
80liters.
So the quantity of water to be added is 80-20=60.
Shipra purohit said:
1 decade ago
Its very simple. Given mixture is 60 litres.
Now given ratio is 2:1 and new one is 1:2.
A:B
Old - 2:1.
New - 1:2.
Value of A should be same so multiply 2 in new one.
=> new - 2:4.
Now value of B differs so subtract them.
4-1 = 3.
Now from formula we get:
(60*3)/(2+1).
=> (60*3)/3.
=> 60.
Now given ratio is 2:1 and new one is 1:2.
A:B
Old - 2:1.
New - 1:2.
Value of A should be same so multiply 2 in new one.
=> new - 2:4.
Now value of B differs so subtract them.
4-1 = 3.
Now from formula we get:
(60*3)/(2+1).
=> (60*3)/3.
=> 60.
Ravi said:
8 years ago
We have 60 liters of the mixture with help of milk and water which means,
2x+1x=60.
3x=60x=20.
Now put the value of x in 2x and 1x. We get 40and20.
And question says that some quantity is further added to Water let take x. So.
40 (milk) /20 (water) +x=1/2.
40/20+x=1/2=>80=20+x.
X=60. Hence proved.
2x+1x=60.
3x=60x=20.
Now put the value of x in 2x and 1x. We get 40and20.
And question says that some quantity is further added to Water let take x. So.
40 (milk) /20 (water) +x=1/2.
40/20+x=1/2=>80=20+x.
X=60. Hence proved.
Surbhi said:
9 years ago
Can anybody please answer this question?
The ratio of milk to water in the first container = 5 : 1.
The ratio of milk to water in the second container = 7 : 2.
In what ratio the mixtures of this two container should be added together so that the quantity of milk in the new mixture may become 80 %?
The ratio of milk to water in the first container = 5 : 1.
The ratio of milk to water in the second container = 7 : 2.
In what ratio the mixtures of this two container should be added together so that the quantity of milk in the new mixture may become 80 %?
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