Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 3)
3.
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
Answer: Option
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x - 3x = 1000
x = 1000.
B's share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
Discussion:
77 comments Page 2 of 8.
Jeeva said:
5 years ago
The question that means if c gets 1000 more than d and this is a keyword.
That's while: c refers as 4x and d refers as 3x. which means 4x + 1000=3x
=> 4x-3x=1000
X=1000.
Thereby sub x=1000 in all term,
5x=5000 as A share,
2x=2000 as B share,
4x=4000as C share,
And 3x=3000 as D share.
That's while: c refers as 4x and d refers as 3x. which means 4x + 1000=3x
=> 4x-3x=1000
X=1000.
Thereby sub x=1000 in all term,
5x=5000 as A share,
2x=2000 as B share,
4x=4000as C share,
And 3x=3000 as D share.
(6)
SUNIDHI SANDEEP KONDEKAR said:
9 months ago
Agree, option C : 2000 is the correct answer.
(4)
Siddhanta said:
3 years ago
Can anyone please explain me the sum in detail?
(3)
Abisheak said:
6 years ago
Simple way to solve:
A : B : C : D = 5 : 2 : 4 : 3.
In this ratio, B's value =2.
B's share =1000(given) * 2 = 2000(option c).
A : B : C : D = 5 : 2 : 4 : 3.
In this ratio, B's value =2.
B's share =1000(given) * 2 = 2000(option c).
(2)
Ralph said:
8 years ago
Sepo Thabo shared sweets in the ratio 5:3. If Thabo had 15 sweets how many sweets did sepo received? Please answer.
(2)
Santhosh said:
7 years ago
In the question he didn't mention that money is equally distributed, so how could all take it as var x for all?
(1)
Sartaj said:
7 years ago
Thanks every one.
The simplest solution I found is;
a:b:c:d
5:2:4:3
let the amounts be;
5x,2x,4x, and 3x respectively.
then according to the condition.
1000=c-d.
1000=4x-3x.
1000=1x.
Since;
b=2x.
Therefore.
b=2(1000),
b=2000.
The simplest solution I found is;
a:b:c:d
5:2:4:3
let the amounts be;
5x,2x,4x, and 3x respectively.
then according to the condition.
1000=c-d.
1000=4x-3x.
1000=1x.
Since;
b=2x.
Therefore.
b=2(1000),
b=2000.
(1)
Umamahesh said:
1 decade ago
We can solve it by also the following method;
let the sum of the money be X.
then,5X/14+2X/14+4X/14+3X/14=X. [because(5+2+4+3=14)
A's share=5X/14,B's share=2X/14,C's share=4X/14 and D's share=3X/14
It is given that C gets Rs. 1000 more than D,
i.e, 4X/14=1000+3X/14
4X/14-3x/14=1000
X/14=1000
X=14000.
So, B's share is 2X/14=2*14000/14 = 2000 Rs.
let the sum of the money be X.
then,5X/14+2X/14+4X/14+3X/14=X. [because(5+2+4+3=14)
A's share=5X/14,B's share=2X/14,C's share=4X/14 and D's share=3X/14
It is given that C gets Rs. 1000 more than D,
i.e, 4X/14=1000+3X/14
4X/14-3x/14=1000
X/14=1000
X=14000.
So, B's share is 2X/14=2*14000/14 = 2000 Rs.
(1)
Setor said:
7 years ago
@All.
According to me;
From the question; C gets 1000 more than D.
Hence C= 1000+D --> (1)
Now from the proportion given, A:B:C:D is equal to 5:2:4:3.
We can then say C:D = 4:3.
or C/D = 4/3 ---> (2)
Put equation (1) into (2)
4/3 = (1000 +D)/ D (using change of subject D= 3000).
Remember the unknown is B.
hence utilizing the proportion with the known values:
2:4 = B: C.
2/4 = B/(1000+3000) NB: c= 1000 +D from equation 1.
Thus using a change of subject B = 2000.
According to me;
From the question; C gets 1000 more than D.
Hence C= 1000+D --> (1)
Now from the proportion given, A:B:C:D is equal to 5:2:4:3.
We can then say C:D = 4:3.
or C/D = 4/3 ---> (2)
Put equation (1) into (2)
4/3 = (1000 +D)/ D (using change of subject D= 3000).
Remember the unknown is B.
hence utilizing the proportion with the known values:
2:4 = B: C.
2/4 = B/(1000+3000) NB: c= 1000 +D from equation 1.
Thus using a change of subject B = 2000.
D Babu said:
9 years ago
a=5000, b=2000, c=4000, d=3000 c value greater then d 1000.
So, B shear 2000.
So, B shear 2000.
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