Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 4)
4.
Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
Answer: Option
Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
|
![]() |
140 | x 5x | ![]() |
, | ![]() |
150 | x 7x | ![]() |
and | ![]() |
175 | x 8x | ![]() |
| 100 | 100 | 100 |
7x, |
21x | and 14x. |
| 2 |
The required ratio = 7x : |
21x | : 14x |
| 2 |
14x : 21x : 28x
2 : 3 : 4.
Discussion:
89 comments Page 8 of 9.
Sonal mahajan said:
1 decade ago
Hi ramesh
Can you tell me please how it comes?
70: 105: 140 or
14: 21: 28 or
2: 3: 4
Can you tell me please how it comes?
70: 105: 140 or
14: 21: 28 or
2: 3: 4
(1)
Neelam said:
1 decade ago
As 5:7:8 totals to 20 so can we assume value say 2000 and can make proportion of value in the given ratio,and then can increase the value by the given percentage of 40,50 and 75,by doing this i m getting increased ratio as 2:3.5:6 can u please make me understand by this method.
RAHUL SINGH said:
1 decade ago
Let their Ratio be 5X,7X,8X. INCRISED %=140%,150%,175%
ATQ , 5X OF 140=7X,150%OF 7X=21/2X,175%OF 8X=12.
Their Ratio = 7X:21/2X:14X.
Taking LCM of Denominator, we get = 14:21:28=2:3:4
ATQ , 5X OF 140=7X,150%OF 7X=21/2X,175%OF 8X=12.
Their Ratio = 7X:21/2X:14X.
Taking LCM of Denominator, we get = 14:21:28=2:3:4
Satish said:
1 decade ago
Hi guys cool,
5:7:8
5*1.4 : 7*1.5 : 8*1.75
7 : 10.5 : 14
2 : 3 :4
Important NOTE : KEEP in fractions instead of decimals.
5:7:8
5*1.4 : 7*1.5 : 8*1.75
7 : 10.5 : 14
2 : 3 :4
Important NOTE : KEEP in fractions instead of decimals.
Gnaneswar said:
1 decade ago
Singh concept is correct.
Kushi said:
1 decade ago
Thanks harjinder.
Priyabrata said:
1 decade ago
Thanks Harjinder, Very easy method apply you.
Emani karthik Reddy said:
1 decade ago
Thanks singh for easy to solve the problems.Keep it up.
Sunita said:
1 decade ago
Very good and easy method singh. Keep it up.
Harjinder Singh said:
1 decade ago
1. 40% of 5 = 2, total seats 5+2=7
2. 50% of 7 = 7/2 total seats 7+7/2=21/2
3. 75% of 8 = 6 total seats 8+6=14
now compare ratios of all 7:21/2:14=>14:21:28
=>2:3:4
2. 50% of 7 = 7/2 total seats 7+7/2=21/2
3. 75% of 8 = 6 total seats 8+6=14
now compare ratios of all 7:21/2:14=>14:21:28
=>2:3:4
(2)
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The required ratio = 7x :