Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 1)
1.
A and B together have Rs. 1210. If 
of A's amount is equal to 
of B's amount, how much amount does B have?
of A's amount is equal to of B's amount, how much amount does B have?
Answer: Option
Explanation:
| 4 | A | = | 2 | B | |
| 15 | 5 |
 A = |
 |
2 | x | 15 |  B |
| 5 | 4 |
| A = |
3 | B |
| 2 |
| |
A | = | 3 |
| B | 2 |
A : B = 3 : 2.
 B's share = Rs. |
|
1210 x | 2 | |
= Rs. 484. |
| 5 |
Discussion:
162 comments Page 4 of 17.
Trimurthulu said:
7 years ago
A+B Total value is R.s 1210.
So Directly we can Calculate B share,
Acc to the question B share 2/5,
Thus 1210 of 2/3,
= 1210 * 2/3,
= 484 RS.
So Directly we can Calculate B share,
Acc to the question B share 2/5,
Thus 1210 of 2/3,
= 1210 * 2/3,
= 484 RS.
Ramesh said:
1 decade ago
Nice one more method
1210 is total of 2 members
Assume b is x
therefore is A is 1210-x
so 4/15*(1210-x)=2/5*x
4(1210-x)=6x
10x=4840
x=484
1210 is total of 2 members
Assume b is x
therefore is A is 1210-x
so 4/15*(1210-x)=2/5*x
4(1210-x)=6x
10x=4840
x=484
Bhuvi said:
1 decade ago
Hey rekha,
It is nothing.They used the formula
To find a=total amt given*(a ratio/a+b ratio)
To find b=total amt given*(b ratio/a+b ratio)
It is nothing.They used the formula
To find a=total amt given*(a ratio/a+b ratio)
To find b=total amt given*(b ratio/a+b ratio)
Thejaswi said:
1 decade ago
A+B=1210
(4/15)A=(2/15)B
A=(15/4)(2/5)B
A/B=3/2
Take it as A/3=B/2
Adding denominators 5P.
So,5P=1210
P=242
B's Amount is 2P i.e,2(242)=484
(4/15)A=(2/15)B
A=(15/4)(2/5)B
A/B=3/2
Take it as A/3=B/2
Adding denominators 5P.
So,5P=1210
P=242
B's Amount is 2P i.e,2(242)=484
Pooja said:
1 month ago
A : B = 3 : 2, total = ₹1210.
2. Total parts = 3 + 2 = 5 ⇒ 1 part = ₹242
3. A = 3 parts = ₹242 × 3 = ₹726.
Answers:
A = ₹726.
B = ₹484.
2. Total parts = 3 + 2 = 5 ⇒ 1 part = ₹242
3. A = 3 parts = ₹242 × 3 = ₹726.
Answers:
A = ₹726.
B = ₹484.
(16)
Anomie said:
5 years ago
A+B = 1210.
(4/15)A = (2/5)B,
2A = 3B.
Therefore, A = (3B)/2,
and substituting, (3B/2) + B = 1210,
and hence, 5B=2420 => B = 484.
(4/15)A = (2/5)B,
2A = 3B.
Therefore, A = (3B)/2,
and substituting, (3B/2) + B = 1210,
and hence, 5B=2420 => B = 484.
(3)
Sanjay said:
6 years ago
A+B = 1210.
(4/15)A = (2/5)B.
A = (30/20)B.
A = (3/2)B,
A = 1.5B.
A+B = 1210.
.5B+B = 1210.
2.5B = 1210,
B = 1210/2.5,
B = 484.
(4/15)A = (2/5)B.
A = (30/20)B.
A = (3/2)B,
A = 1.5B.
A+B = 1210.
.5B+B = 1210.
2.5B = 1210,
B = 1210/2.5,
B = 484.
NITESH MALAKAR said:
1 decade ago
A+B=1210.
A:B=3:2.
A/B=3/2.
2A=3B.
Therefore, A=(3B)/2.
And substituting, (3B/2)+B=1210.
And hence, 5B=2420 => B=484 Rs.
A:B=3:2.
A/B=3/2.
2A=3B.
Therefore, A=(3B)/2.
And substituting, (3B/2)+B=1210.
And hence, 5B=2420 => B=484 Rs.
Aditya said:
1 decade ago
A three digit number has the ratio of its units digit is the number itself as 1 : 27.
Find its tens digit? Please solve this.
Find its tens digit? Please solve this.
Govind said:
1 decade ago
No need to make complex its easy.
Because of question ask about result of b.
A = 1210, B = 1210;
2/5*B = 2/5*1210.
= 484.
Because of question ask about result of b.
A = 1210, B = 1210;
2/5*B = 2/5*1210.
= 484.
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