Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = | ![]() |
5 x | 3 | ![]() |
: | ![]() |
8 x | 3 | ![]() |
= 3 : | 24 |
| 5 | 5 | 5 |
A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
B = |
![]() |
98 x | 15 | ![]() |
= 30. |
| 49 |
Discussion:
124 comments Page 8 of 13.
Niroj kumar sahooo said:
10 years ago
Thank you @Alisha.
Anjali sharma said:
10 years ago
It is very easy A : B = 2 : 3, B : C = 5 : 8.
Multiply this
2 3
5 8
_______
10 15 24
_________
Then, 98 * 15 / 49 = 30.
Multiply this
2 3
5 8
_______
10 15 24
_________
Then, 98 * 15 / 49 = 30.
Ayush Jain said:
10 years ago
Given,
A : B : C = 98.
A : B = 2 : 3 ---------------> Eq.1.
B : C = 5 : 8 ---------------> Eq.2.
Now Multiply Eq.1 by 5 and Eq.2 by 3 to get B common;
Then,
A : B = 10 : 15.
B : C = 15 : 24.
Then, A : B : C = 10 : 15 : 24.
So, 10X + 15X + 24X = 98.
49X = 98.
X = 2.
Then, the Second Number is 15X.
i.e B = 15 * 2 = 30 => Ans.
A : B : C = 98.
A : B = 2 : 3 ---------------> Eq.1.
B : C = 5 : 8 ---------------> Eq.2.
Now Multiply Eq.1 by 5 and Eq.2 by 3 to get B common;
Then,
A : B = 10 : 15.
B : C = 15 : 24.
Then, A : B : C = 10 : 15 : 24.
So, 10X + 15X + 24X = 98.
49X = 98.
X = 2.
Then, the Second Number is 15X.
i.e B = 15 * 2 = 30 => Ans.
Rashmi said:
10 years ago
@Rajkumar.
Thanks for giving the best and the most simple way to solve this question.
Thanks for giving the best and the most simple way to solve this question.
ADITYA JAIN said:
10 years ago
Let the three ratio be = A:B:C.
A:B = 2:3.
B:C = 5:8.
Now A:B:C = 10:15:24 (2*5 = 10, 3*5 = 15, 3*8 = 24).
Now 10 + 15 + 24 = 49.
B = 98 * 15/49.
= 30.
A:B = 2:3.
B:C = 5:8.
Now A:B:C = 10:15:24 (2*5 = 10, 3*5 = 15, 3*8 = 24).
Now 10 + 15 + 24 = 49.
B = 98 * 15/49.
= 30.
Bhuvana said:
1 decade ago
@Sid.
How can you say total 150 members?
How can you say total 150 members?
Guru said:
1 decade ago
Why should take 8?
Muhammad Usman Shoaib said:
1 decade ago
If are is the remainder when a positive integer is divided by a single- digit prime integer, what is the largest possible value of are?
Options : A 6, B 7, C 8, D 9 and E : It cannot be determined from the information above.
Options : A 6, B 7, C 8, D 9 and E : It cannot be determined from the information above.
Swagger said:
1 decade ago
The easiest way:
a:b:c.
2:3.
5:8.
So 8/5 = 1.6. So c is 1.6 times bigger than b.
So 3*1.6 = 24/5.
Therefore, the ratio is 2:3:24/5.
Simplifying gives ratio as 10:15:24.
To solve the question 10x:15x:24x = 98.
10x+15x+24x = 98,
So 49x = 98, x=2.
Therefore the second number is 15*2 = 30.
a:b:c.
2:3.
5:8.
So 8/5 = 1.6. So c is 1.6 times bigger than b.
So 3*1.6 = 24/5.
Therefore, the ratio is 2:3:24/5.
Simplifying gives ratio as 10:15:24.
To solve the question 10x:15x:24x = 98.
10x+15x+24x = 98,
So 49x = 98, x=2.
Therefore the second number is 15*2 = 30.
MANDEEP SINGH said:
1 decade ago
A:B:C.
2:3.
5:8.
We get A:B:C.
A = 2X5 = 10;
B = 3X5 = 15;
C = 3X8 = 24;
A:B:C = 10:15:24.
10x+15x+24x = 98.
49x = 98.
x = 2.
So B's sum is: 15X2 = 30.
2:3.
5:8.
We get A:B:C.
A = 2X5 = 10;
B = 3X5 = 15;
C = 3X8 = 24;
A:B:C = 10:15:24.
10x+15x+24x = 98.
49x = 98.
x = 2.
So B's sum is: 15X2 = 30.
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A : B : C = 2 : 3 :