Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = |  |
5 x | 3 |  |
: | |
8 x | 3 | |
= 3 : | 24 |
| 5 | 5 | 5 |
 A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
| B = |
|
98 x | 15 | |
= 30. |
| 49 |
Discussion:
123 comments Page 6 of 13.
Rajkumar said:
1 decade ago
General formula
A:B
B:C
---------------
A*B : B*B : B*C
----------------
A*B + B*B + B*C = sum
Then total should be divided with this sum
Ans = total / sum
This ans should be multiplied with each ratios to get a desired number
In the same way
2:3
5:8
-------
10:15:24 (2*5 : 3*15 : 3*8)
Then adding 10+15+24 gives 49
This 49 divides 98
98 / 49 = 2
B = 2*15 = 30
Similarly
A = 2 * 10 = 20
C = 2 * 24 = 48
A:B
B:C
---------------
A*B : B*B : B*C
----------------
A*B + B*B + B*C = sum
Then total should be divided with this sum
Ans = total / sum
This ans should be multiplied with each ratios to get a desired number
In the same way
2:3
5:8
-------
10:15:24 (2*5 : 3*15 : 3*8)
Then adding 10+15+24 gives 49
This 49 divides 98
98 / 49 = 2
B = 2*15 = 30
Similarly
A = 2 * 10 = 20
C = 2 * 24 = 48
Sana said:
1 decade ago
Kalpa and Abhishek gave best n easy methods, thank you :).
Amruta said:
1 decade ago
Thanks kalpana:).
PravinBabu said:
1 decade ago
Excellent Alisha
Nena said:
1 decade ago
I have a question please solve it. If A:B=2:3, B:C=4:5, and C:D= 6:7 then find the value of A:B:C:D.
Rupam said:
1 decade ago
A:B = 2:3.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
So the second number(B) is: (98*15/49) = 30.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
So the second number(B) is: (98*15/49) = 30.
Sid said:
1 decade ago
@jay namdev we have Rs.58.
IN 58 25 paise is = 58*4 = 232.
In 58 50 paise is = 58*2 = 116.
Ratio of 50 paise : 25 paise 1:2.
Total 150 student it means if boys is 50 then girls is 100.
100+50 =150.
It means total girls in class is 100.
IN 58 25 paise is = 58*4 = 232.
In 58 50 paise is = 58*2 = 116.
Ratio of 50 paise : 25 paise 1:2.
Total 150 student it means if boys is 50 then girls is 100.
100+50 =150.
It means total girls in class is 100.
Elizabeth Scaria said:
1 decade ago
If a:b=m:n and b:c=p:q then a:b:c= mp:np:nq.
Here,
a:b=2:3 .
b:c=5:8.
Then a:b:c become 10:15:24.
If sum of money S is divided in the ratio a:b:c then part of b is
= (b/a+b+c)*S.
Now here part of B become (15/49)*98 = 30.
Here,
a:b=2:3 .
b:c=5:8.
Then a:b:c become 10:15:24.
If sum of money S is divided in the ratio a:b:c then part of b is
= (b/a+b+c)*S.
Now here part of B become (15/49)*98 = 30.
Chandan said:
1 decade ago
A:B = 2:3.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
Let the ratio of numbers be 10x:15x:24x.
According to question,
10x+15x+24x = 98.
49x = 98.
x = 98/49.
x = 2.
Now 2nd number is 15x.
i.e;15*2 = 30.
B:C = 5:8.
(2:3)x5 = 10:15.
(5:8)x3 = 15:24.
A:B:C = 10:15:24.
Let the ratio of numbers be 10x:15x:24x.
According to question,
10x+15x+24x = 98.
49x = 98.
x = 98/49.
x = 2.
Now 2nd number is 15x.
i.e;15*2 = 30.
Divi said:
1 decade ago
Explain the whole problem clearly and step by step.
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