Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = | ![]() |
5 x | 3 | ![]() |
: | ![]() |
8 x | 3 | ![]() |
= 3 : | 24 |
| 5 | 5 | 5 |
A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
B = |
![]() |
98 x | 15 | ![]() |
= 30. |
| 49 |
Discussion:
123 comments Page 13 of 13.
Saurabh Kumar said:
6 years ago
@All.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Jarmy said:
5 years ago
How come 49?
B = 98 * 15/49.
B = 98 * 15/49.
Shafiya anjum. said:
5 years ago
Well explained, thanks @Alisha.
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A : B : C = 2 : 3 :