Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 9)
9.
The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option
Explanation:
Let the three parts be A, B, C. Then,
| A : B = 2 : 3 and B : C = 5 : 8 = | ![]() |
5 x | 3 | ![]() |
: | ![]() |
8 x | 3 | ![]() |
= 3 : | 24 |
| 5 | 5 | 5 |
A : B : C = 2 : 3 : |
24 | = 10 : 15 : 24 |
| 5 |
B = |
![]() |
98 x | 15 | ![]() |
= 30. |
| 49 |
Discussion:
124 comments Page 3 of 13.
Kanchan said:
6 years ago
For making B in the ratio equal.
A:B =5*2:3*5
B:C = 3*5:8*3
A:B:C become,
10:15:24.
Now let multiple ratio by x.
10x:15x:24x.
As given;
10x + 15x + 24x = 98
49x = 98.
x = 2.
Now the second no.is 15x.
So, 15x2= 30.
Therefore the Correct answer is B.
A:B =5*2:3*5
B:C = 3*5:8*3
A:B:C become,
10:15:24.
Now let multiple ratio by x.
10x:15x:24x.
As given;
10x + 15x + 24x = 98
49x = 98.
x = 2.
Now the second no.is 15x.
So, 15x2= 30.
Therefore the Correct answer is B.
(3)
Nitika said:
6 years ago
a:b = 2:3,
C:d = 5:8,
a:b:c= 10:15:24.
And 10+15+24 = 49 but their total given is 98.
So, we will multiply 49 by 2(because. Their total is 98 not 49) which will be 98.
Now; as in question they have asked to find the second number. So we will now multiply 15 by 2 = 30 answer.
C:d = 5:8,
a:b:c= 10:15:24.
And 10+15+24 = 49 but their total given is 98.
So, we will multiply 49 by 2(because. Their total is 98 not 49) which will be 98.
Now; as in question they have asked to find the second number. So we will now multiply 15 by 2 = 30 answer.
(2)
Jarmy said:
6 years ago
How come 49?
B = 98 * 15/49.
B = 98 * 15/49.
Manisha said:
6 years ago
Let the three numbers be x, y and z.
x : y : z
2 : 3
-----5 : 8.
= 10 : 15 : 24 (2*5 : 3*5 : 3*8).
= 10 + 15 + 24 = 49.
for B = 98 * 15/49,
=30.
x : y : z
2 : 3
-----5 : 8.
= 10 : 15 : 24 (2*5 : 3*5 : 3*8).
= 10 + 15 + 24 = 49.
for B = 98 * 15/49,
=30.
(2)
Rezvi said:
6 years ago
Well said, Thanks @Kalpa.
(1)
Saurabh Kumar said:
6 years ago
@All.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Solution:
A: B = 2:3 and B: C = 5:8.
So Multiply A: B by 5 and B: C by 3.
So, we got a common B.
A: B = 10:15 and B: C = 15:24.
Total sum = 10+15+24 = 49,
Now, we want B so we simply.
B = (15/49)*Sum of total numbers (GIVEN).
B = (15/49)*98.
we get 30.
Dhanakar said:
6 years ago
2:3
--5:8
_______
10:15:24
________
Now total sum is 98.
Then 10+15+24=49.
(98*15/49)=(2*15)=30.
--5:8
_______
10:15:24
________
Now total sum is 98.
Then 10+15+24=49.
(98*15/49)=(2*15)=30.
Rahul kumar said:
6 years ago
x:y:z
2:3:3 ~1
5:5:8 ~2
Then multiply 1 and 2 we get 10:15:24.
10+15+24 = 98.
49 = 98.
1 = 2.
15x2 = 30.
2:3:3 ~1
5:5:8 ~2
Then multiply 1 and 2 we get 10:15:24.
10+15+24 = 98.
49 = 98.
1 = 2.
15x2 = 30.
Tejkumar Ch said:
6 years ago
A:B =2:3.
B:C = 5:8.
A:B:C = 10:15:24.
Therefore,
A=98*10/49;
B=98*15/49;
C=98*24/49;
Hence the result is easy.
B:C = 5:8.
A:B:C = 10:15:24.
Therefore,
A=98*10/49;
B=98*15/49;
C=98*24/49;
Hence the result is easy.
NITHI said:
7 years ago
2:3. 2*5=10. 5*3=15. 3*8=24
5:8. 15/49*98=30.
It is easy for time saving the exam.
5:8. 15/49*98=30.
It is easy for time saving the exam.
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A : B : C = 2 : 3 :