Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 15)
15.
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs. | ![]() |
25x | + | 10 x 2x | + | 5 x 3x | ![]() |
= Rs. | 60x |
100 | 100 | 100 | 100 |
![]() |
60x | = 30 | ![]() |
30 x 100 | = 50. |
100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
Discussion:
117 comments Page 7 of 12.
Pricilla said:
1 decade ago
Please give the proper answer with solution.
Richa said:
10 years ago
My answer came 300 coins.
Rs. 30 = 30*100 = 3000 p.
Ratio = 1:2:3 then 3000*3/6 = 1500 p.
i.e. 1500/5 = 300.
Therefore, there are 300 5p coins.
Isn't it correct? Please explain me.
Rs. 30 = 30*100 = 3000 p.
Ratio = 1:2:3 then 3000*3/6 = 1500 p.
i.e. 1500/5 = 300.
Therefore, there are 300 5p coins.
Isn't it correct? Please explain me.
Waleed said:
9 years ago
The right answer is 150.
We can not equate quantity to value e.g 1:2:3 or 1x+2x+3x(Q) = 3000(V).
We should equate value to value e.g 25p 10p 5p or 25x 20x 15x(V) = 3000(V).
that makes 60x=3000 and x=50.
Proof:
With the answer 150 5p coins we get,
1:2:3 = 50 100 150 , 25p 10p 5p respectively makes a value of 3000p and it is logical with the given ratio 1:2:3/50:100:150 [50 coins of 25p] [100 coins of 10p] and [150 coins of 5p].
Whereas, with the answer 300 5p coins we get,
1:2:3 = 20 100 300 , 25p 10p 5p respectively, also makes a value of 3000p but it is illogical with the ratio. It can't be 1:2:3/20:100:300.
Hope you got it :).
We can not equate quantity to value e.g 1:2:3 or 1x+2x+3x(Q) = 3000(V).
We should equate value to value e.g 25p 10p 5p or 25x 20x 15x(V) = 3000(V).
that makes 60x=3000 and x=50.
Proof:
With the answer 150 5p coins we get,
1:2:3 = 50 100 150 , 25p 10p 5p respectively makes a value of 3000p and it is logical with the given ratio 1:2:3/50:100:150 [50 coins of 25p] [100 coins of 10p] and [150 coins of 5p].
Whereas, with the answer 300 5p coins we get,
1:2:3 = 20 100 300 , 25p 10p 5p respectively, also makes a value of 3000p but it is illogical with the ratio. It can't be 1:2:3/20:100:300.
Hope you got it :).
Raj said:
9 years ago
Total amount according to ratio is (1x25+2x10+3x5) = 60 paise.
If 60 paise ----> 3000 paise.
Then 5 paise-----> ? (5x3000/60=50).
Hence the answer is : 50 x 3 = 150( here 3 is ratio of 5p).
If 60 paise ----> 3000 paise.
Then 5 paise-----> ? (5x3000/60=50).
Hence the answer is : 50 x 3 = 150( here 3 is ratio of 5p).
Jaris said:
9 years ago
If and 300 means,
As per the ratio: 100*25 +200*10 +300*5.
= 2500+2000+1500.
=6000 Paise.
So 60Rs came. So that is wrong.
If answer is 150 means,
50*25+100*10+150*5 = 1250+1000+750 = 3000.
Rs 30... So 150 is the correct answer.
As per the ratio: 100*25 +200*10 +300*5.
= 2500+2000+1500.
=6000 Paise.
So 60Rs came. So that is wrong.
If answer is 150 means,
50*25+100*10+150*5 = 1250+1000+750 = 3000.
Rs 30... So 150 is the correct answer.
Aliya said:
9 years ago
In a wallet, there are 50 p, 25 p and 1 Rs coins in the ratio 6 : 8 : 5. If the wallet contains Rs. 210 in total, find the number of 1 Rupee coins?
Suba said:
9 years ago
How will you get in last step 3?
Can you please explain.
Can you please explain.
Sandeep said:
9 years ago
Please answer.
A bag contains coins of 1rs, 50p, 25p in the ratio of their value as 13:11:7.
The total number of coins in the bag are 378, find 25p coins in a bag.
A bag contains coins of 1rs, 50p, 25p in the ratio of their value as 13:11:7.
The total number of coins in the bag are 378, find 25p coins in a bag.
Bala said:
9 years ago
25p : 10p : 5p = 1 : 2 : 3 = Rs.30.
1rs = 4 * 25p (or) 25p = 1/4.
Similarly, 10p = 1/10 and 5p = 1/20.
x/4 + 2x/10 + 3x/20 = 30.
x = 50
Answer:
25p = 50.
10p = 100.
5p = 150.
1rs = 4 * 25p (or) 25p = 1/4.
Similarly, 10p = 1/10 and 5p = 1/20.
x/4 + 2x/10 + 3x/20 = 30.
x = 50
Answer:
25p = 50.
10p = 100.
5p = 150.
Priyanka Bulla said:
9 years ago
Could you explain why we do not take the sum of ratios in the denominator i.e. (25x/100 + 20x/100 + 15x/100)/6 ?
Because in some problems they have considered the values like 150*2 + 25*2 and then have divided by sum of ratios i.e 4. Please clarify it.
Because in some problems they have considered the values like 150*2 + 25*2 and then have divided by sum of ratios i.e 4. Please clarify it.
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