Aptitude - Ratio and Proportion - Discussion
Discussion Forum : Ratio and Proportion - General Questions (Q.No. 14)
14.
Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:
Answer: Option
Explanation:
Let the numbers be 3x and 5x.
| Then, | 3x - 9 | = | 12 |
| 5x - 9 | 23 |
23(3x - 9) = 12(5x - 9)
9x = 99
x = 11.
The smaller number = (3 x 11) = 33.
Discussion:
27 comments Page 1 of 3.
Bharath said:
8 years ago
This question can be solved very easily.
Here the first ratio is a : b :: 3 : 5 that means "a" should be in multiples of 3 so the answer in the option must be either 33 or 27.
The next part is it is subtracted by 9 then the answer should satisfy ratio 12 : 23. So if 27 - 9 = 18 it is not multiple of 12 but 33 - 9 = 24.
24 is multiple of 12 so 24 is the answer.
Here the first ratio is a : b :: 3 : 5 that means "a" should be in multiples of 3 so the answer in the option must be either 33 or 27.
The next part is it is subtracted by 9 then the answer should satisfy ratio 12 : 23. So if 27 - 9 = 18 it is not multiple of 12 but 33 - 9 = 24.
24 is multiple of 12 so 24 is the answer.
(12)
Zainab said:
7 years ago
It can be slove like this please let me know?
New ration is;
12:23:=36.
36-9=33.
New ration is;
12:23:=36.
36-9=33.
(9)
Ramzan said:
2 years ago
How we got 9x=99?
(7)
Vishal said:
7 years ago
Easy and best way Subtract 1st number to 2nd number of new ratio i.e. 12-23.
So, the difference = 11 so we got each fraction number for ration so, 11 per fraction * small 1st ratio number i.e.3 so, 11*3=33.
So, the difference = 11 so we got each fraction number for ration so, 11 per fraction * small 1st ratio number i.e.3 so, 11*3=33.
(7)
Parul said:
1 decade ago
Its simplification if the equation:
23(3x-9)=12(5x-9)
69x-207=60x-108
69x-60x=-108+207
9x=99
x=11
23(3x-9)=12(5x-9)
69x-207=60x-108
69x-60x=-108+207
9x=99
x=11
(3)
Bhavik said:
5 years ago
x/y = 3/5. Than,
x-9/y-9 = 12/23.
Now solve both the equation.
23x-12y=99 and 5x-3y=0.
Therefore x=33 and y=55.
So smaller no. is 33.
x-9/y-9 = 12/23.
Now solve both the equation.
23x-12y=99 and 5x-3y=0.
Therefore x=33 and y=55.
So smaller no. is 33.
(3)
Francis Vivian said:
7 months ago
x/y = 3/5 -> y = 5x/3.
-> (x-9) / (y-9) = 12/23.
-> 23(x-9) = 12(y-9).
-> 23x - 207 = 12y - 108.
-> 23x - 12(5x/3) = 207 - 108.
-> 3x = 99.
-> x = 99/3 = 33.
-> (x-9) / (y-9) = 12/23.
-> 23(x-9) = 12(y-9).
-> 23x - 207 = 12y - 108.
-> 23x - 12(5x/3) = 207 - 108.
-> 3x = 99.
-> x = 99/3 = 33.
(2)
Juke said:
8 years ago
Let x be the smaller number.
y be the larger number.
1st equation:
(x/y)=(3/5)
2nd equation:
(x-9)/(y-9)=12/23.
Then solve for x and y.
x = 33 and y = 55.
Though my solution is different i still arrive at the same answer.
I think my equation is easy to understand.
y be the larger number.
1st equation:
(x/y)=(3/5)
2nd equation:
(x-9)/(y-9)=12/23.
Then solve for x and y.
x = 33 and y = 55.
Though my solution is different i still arrive at the same answer.
I think my equation is easy to understand.
(2)
ADITYA MISHRA said:
9 years ago
3/5=2R (5-3=2 i.e. difference).
12/23=11R (23-12=11).
3/5*11 multiply by 2nd difference = 33/55.
12/23*2 multiply by 1st difference = 24/46.
9R = 9 i.e R = 1. So that smaller no 33.
12/23=11R (23-12=11).
3/5*11 multiply by 2nd difference = 33/55.
12/23*2 multiply by 1st difference = 24/46.
9R = 9 i.e R = 1. So that smaller no 33.
Vishal Bhagure said:
3 years ago
I am getting x = 8.
By taking 3 as common multiple and dividing the same by 12.
By taking 3 as common multiple and dividing the same by 12.
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