Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 8)
8.
In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Answer: Option
Explanation:
A : B = 100 : 80.
A : C = 100 : 72.
 |
B | = |  |
B | x | A |  |
= | |
80 | x | 100 | |
= | 10 | = | 100 | = 100 : 90. |
| C | A | C | 100 | 72 | 9 | 90 |
B can give C 10 points.
Discussion:
13 comments Page 2 of 2.
Kiran said:
8 years ago
@All.
In 100 point game b gets only 80 point and C gets 72 point.
Where B gets 80, C can get 72 point, here at this time B gets 80 points but in our question, we need to calculate for 100 points.
WIn 80 point game B beat C by 8 point.
Then in 100 point game B beat C by 10 point.
80---------8
100-------?
(100*8)÷80=10.
In 100 point game b gets only 80 point and C gets 72 point.
Where B gets 80, C can get 72 point, here at this time B gets 80 points but in our question, we need to calculate for 100 points.
WIn 80 point game B beat C by 8 point.
Then in 100 point game B beat C by 10 point.
80---------8
100-------?
(100*8)÷80=10.
Pavithra said:
5 years ago
Why multiple 10/9 with 10?
Maka M said:
5 years ago
We can use it in other way.
A:B:C = 100:80:72.
Here the question calculate the B can give C. So;
B:C =80 :72 ------B/C=80/72.
B is 100 points then C = 72B/80 here B = 100
C= (72 * 100)/80 = 90.
So, B can give C is = 100 - 90 = 10.
A:B:C = 100:80:72.
Here the question calculate the B can give C. So;
B:C =80 :72 ------B/C=80/72.
B is 100 points then C = 72B/80 here B = 100
C= (72 * 100)/80 = 90.
So, B can give C is = 100 - 90 = 10.
(2)
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