Aptitude - Races and Games - Discussion
Discussion Forum : Races and Games - General Questions (Q.No. 6)
6.
In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by:
Answer: Option
Explanation:
A : B = 200 : 169.
A : C = 200 : 182.
C | = | ![]() |
C | x | A | ![]() |
= | ![]() |
182 | x | 200 | ![]() |
= 182 : 169. |
B | A | B | 200 | 169 |
When C covers 182 m, B covers 169 m.
When C covers 350 m, B covers | ![]() |
169 | x 350 | ![]() |
= 325 m. |
182 |
Therefore, C beats B by (350 - 325) m = 25 m.
Discussion:
20 comments Page 2 of 2.
Satyaki said:
3 years ago
22.75 is the correct answer solving by speed distance time method.
(2)
Smritimay said:
1 decade ago
A can beat B by 31, then (total distance-A beat B) = 200-31 = 169.
Sravanthi said:
7 years ago
Could you please give me the detailed explanation?
Sunita said:
1 decade ago
From where 325 came. Multiplication result wrong.
Sukriti said:
1 decade ago
But the race finishes as A covers 350 distance?
Priya said:
6 years ago
How 169 will come over here? Please explain.
Rony said:
5 years ago
How C/B=(C/A*A/B) come?
Please explain.
Please explain.
(1)
Xyz said:
1 decade ago
From Where did you get the 200 and 169
Ritvik said:
5 years ago
22.75 is the correct answer.
J. Prakash said:
6 years ago
Here 200m - 31m = 169.
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